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zhenek [66]
3 years ago
10

Q1 0.06 million = 6.2 thousand = Give your answer to two de

Mathematics
1 answer:
sukhopar [10]3 years ago
5 0
600.2 million will be the answer
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Here is part of a train timetable.
Fofino [41]
He has to wait 13 minutes for the 7:18 train
5 0
3 years ago
The variable b is equal to 160 more than the product of 5 and c. The variable b is equal to 304 decreased by 3 times c. What is
frosja888 [35]
B=160+ 5c
b= 304- 3c

160+5c=304-3c
+3c             +3c
160+8c=304
-160       -160
8c= 144
c=18
4 0
4 years ago
Please help!! 20 POINTS
shepuryov [24]
<h2>Hello!</h2>

The answers are:

First image:

The answer is the second option, the angles is 53\°

Second image:

The answer is the third option:

\frac{5}{13}

Third image:

The length of the adjacent leg is the first option:

8\sqrt{2}units

Fourth image:

The answer is the fourth option, 72\°

Fifth image:

The answer is the fourth option, DF (hypothenuse) is equal to 25 units.

<h2>Why?</h2>

To solve these problems, we need to use the following trigonometric identities and the Pythagorean Theorem, since we are working with right triangles.

Tan(\alpha)=\frac{y}{x}\\\\(Tan(\alpha))^{-1} =(\frac{y}{x})^{-1}\\\\\alpha =Arctan(\frac{y}{x})

Sin(\alpha)=\frac{opposite}{hypothenuse}

Pythagorean Theorem:

c^{2}=a^{2} +b^{2}

So, solving we have:

First image:

We are given a right triangle that has the following lengths:

base=x=6units\\height=y=8units\\hypothenuse=10units

Then, calculating we have:

\alpha =Arctan(\frac{y}{x})\\\\\alpha =Arctan(\frac{8}{6})\\\\\alpha =Arctan(1.33)\\\\\alpha =53\°

Hence, the answer is the second option, the angles is 53\°

Second image:

We are given a right triangle that has the following lengths:

base=x=12units\\height=y=5units\\hypothenuse=13units

Then calculating the sin ratio, we have:

Sin(\alpha)=\frac{opposite}{hypothenuse}

Sin(\alpha)=\frac{5}{13}

Thence, the answer is the third option:

\frac{5}{13}

Third Image:

We are given the following information:

hypothenuse=16units\\\\\alpha =45\°

Then, calculating one of the angle legs, since both will have the same length, using the sine trigonometric identity, we have:

Sin(\alpha)=\frac{Opposite}{Hypothenuse}\\ \\Sin(45\°)=\frac{Opposite}{16}\\\\Opposite=Sin(45\°)*16\\\\Opposite=\frac{\sqrt{2} }{2}*16=8\sqrt{2}

Hence, the answer is the first option the length of the adjacent leg is

Opposite=\frac{\sqrt{2} }{2}*16=8\sqrt{2}units

Fourth image:

We are given the following information:

base=x=9units\\height=y=3units

To calculate the angle at the B vertex, first, we need to calculate the angle at the C vertex, and then, calculate the B vertex by the following way:

Since the sum of all the interior angles of a triangle are equal to 180°, we have that:

180\°=Angle_{B}+Angle{C}+90\°

Angle_{B}=180\° -90\°-Angle_{C}

So, calculating the angle at the C vertex, we have:

\alpha =Arctan(\frac{y}{x})

\alpha =Arctan(\frac{3}{9})

\alpha =Arctan(0.33)=18.26\°

Then, calculating the angle at the B vertex, we have:

Angle_{B}=180\° -90\°-18.26\°=71.74\°=71.8\°=72\°

Hence, the answer is the fourth option, 72\°

Fifth image:

We are given the following information:

base=x=24units\\height=y=7units

Now, to calculate the distance DF (hypothenuse) we need to use the Pythagorean Theorem:

c^{2}=a^{2} +b^{2} \\\\hypothenuse^{2}=adjacent^{2}+opposite^{2}\\\\\sqrt{hypothenuse^{2}}=\sqrt{adjacent^{2}+opposite^{2}}\\\\hypothenuse=\sqrt{adjacent^{2}+opposite^{2}}

Then, substituting we have:

hypothenuse=\sqrt{24^{2}+(7)^{2}}

hypothenuse=\sqrt{576+49}=\sqrt{625}

hypothenuse=\sqrt{625}

hypothenuse=25units

Hence, the answer is the fourth option, DF (hypothenuse) is equal to 25 units.

Have a nice day!

4 0
3 years ago
Try This question out and I’ll give you brainliest
ArbitrLikvidat [17]

Answer:

7/12ths

Step-by-step explanation:

2/3rds of the way full would be 8/12. Since she started at 1/12th of a tank, 7/12ths was added. (:

7 0
3 years ago
Read 2 more answers
How to do geometry proofs I believe it's the subtraction property
notsponge [240]
Hi there!
You need to prove that line segment DE ≅ GH.

You're given:
Line segment DJ ≅ line segment GJ;
E is the midpoint of line segment DF;
H is the midpoint of line segment GJ.

You can justify that line segment DE ≅ line segment GH with the midpoint definition, which is a point on a line segment that divides it into two equal parts. The two equal parts in this case are line segments DE and GH, so DE ≅ GH.

Please comment with <em></em>any questions!
8 0
3 years ago
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