The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
C. -5y -4 = -(x+3)^2 -1/2
Hope I am right.
Answer:
16
Step-by-step explanation:
2/8 is = to 1/4
4/16 is = to 1/4
GIVE ME BRAINLIESTTTTT
Always simplify expressions in the order of PMDAS
(Parenthesis, Multiplication, Division, Addition, Subtraction)
(4-1) = (3)
[(1+6) + 2] = [7 + 2] = (9)
(3)x(9) = 27
The answer is 27
Answer:
the answer is the question B!!
Step-by-step explanation: