substitute the values from the quadratic formula.
a= 3
b= -5
c= -3
simplify the numerator
5±√61/2 times 3
Multiply 2 by 3
<h2><em>
ANSWER:5±√61/6</em></h2>
A product is negative when the number of negative numbers in the multiples is odd.
Therefore, options A and C gives negative products.
Answer:
The expression that could be used is (-4)(3) + (-4)(
) ⇒ B
Step-by-step explanation:
Let us revise the distributive property:
<em>The product of a number and the sum of 2 other numbers equal to the sum of the products of the number with the other 2 numbers</em>
We will use this rule to solve the question
∵ The product of -4 and 3 = -4 × 3
→ We can right 3 as (3 + )
∵ 3 = (3 + )
∴ -4 × 3 = -4(3 + )
→ By using the rule above
∵ -4(3 + ) = (-4)(3) + (-4)()
∴ -4 × 3 = (-4)(3) + (-4)()
∴ The expression that could be used is (-4)(3) + (-4)()
Solve by elimination.
The goal is to cancel out one of the variables in order to easily solve for the other variable.
Do this by changing the equations so that the coefficients of either x or y add up to 0.
Notice the coefficients of y are 3 and 3, if we make one of them negative then they add up to 0. 3+ (-3) = 0
Multiply 2nd equation by -1.
6x +3y = 9
-2x -3y = -1
__________
4x +0y = 8
Solve for x
4x = 8
x = 8/4 = 2
Plug x=2 back into one of original equations to find y.
---> 2(2) + 3y = 1
---> 4 + 3y = 1
---> 3y = -3
---> y = -1
Therefore solution is (2,-1)
