To start to find the fraction of the difference that the ferry traveled in one hour, we should look at what information we have now. The equation, so far, is that:
distance =
hour
Since we want to find the distance traveled by the ferry in one hour, we need to multiply by the reciprocal of the fraction in front of the hours, which means we need to multiply both sides by
. Doing this, wee get that the ferry traveled
of the distance in one hour.
Answer:
-4539
Step-by-step explanation:
147 + 130 + 113 + 96 +
arithmetic, with
a = 147 and d 130 - 147 = -17
Sn = (n/2)(2a + d(n - 1))
S34 = (34/2)(2*147 - 17(34 - 1))
= 17(294 - 561)
hope it helps!
Answer:
Choose an equation that has this same slope or the same coefficients of x and y - 2x + 3y.
Step-by-step explanation:
Parallel lines are lines which do not intersect. As a result they have the same slope. The line here is 2x + 3y = 12 which can be rearranged into slope intercept form to find the slope.
2x + 3y = 12
3y = 12 - 2x
y = 4 - 2/3 x
The slope of the line is -2/3. Choose an equation that has this same slope or the same coefficients of x and y - 2x + 3y.
Answer:
Multiply by 3, 162
Step-by-step explanation:
2 x 3 is 6.
6 x 3 is 18.
18 x 3 is 54.
54 x 3 is.... you get the deal.
54 x 3 is 162.
If we take the Pythagorean identity identity sin^2 x + cos^2 x = 1 then
<span>(cos^2 x + sin^2 x) / (cot^2 x - csc^2 x)
The numerator becomes 1 since addition order matters not.
1 / </span>(cot^2 x - csc^2 x)
If we factor the denominator out a negative
1 / -(<span>csc^2 x - cot^2 x)
Consider </span><span>sin^2 x + cos^2 x = 1. Divide both sides by sin^2 x to get
1 + cot^2 x = csc^2 x
Subtract both sides by cot^2 x to get 1 = csc^2 x - cot^2 x.
Replace the denominator
1 / -(1) = -1
For cos</span>^2 θ / sin^2 θ + csc θ sin θ, we use cscθ = 1/sinθ and cosθ/sinθ = cotθ so
= cos^2 θ / sin^2 θ + 1
= cot^2 θ + 1
We use 1 + cot^2 <span>θ = csc^2 </span>θ to simplify this to
= csc^2 θ
Answers: -1
csc^2 θ
