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3 years ago

Point F is on circle C. What is the length of line segment GF?

2 answers:

8 0

The answer:
the full question is as follow:
Point F is on circle C. What is the length of line segment GF?

12.5 units
15.0 units
17.5 units
20.0 units

according to the image, GF= GC + CF

CF is the radius of the circle, so it is CF =CE = 7.5
all that we want to find is the value of GC
let's consider the triangle GEC. This is a right triangle, so for finding GC, we can apply Pythagorean theorem

that is, GE² + EC² = GC², and from this, we have GC = sqrt(GE² + EC² )

GC = sqrt(10² + 7.5² )=sqrt(56.25)=12.5

therefore, GF= GC + CF=12.5 + 7.5 = 20.0
the answer is 20.0 units

Lesechka [4]3 years ago

4 0

Answer:

20.0 units on edge.

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How do i find the volume of these similar solids? round to the nearest tenth HELP

FromTheMoon [43]

Answer:

The volume of the larger solid is $592.6\ mm^3$

Step-by-step explanation:

The question is

If these solids are similar, find the volume of the larger solid

step 1

Find the scale factor

we know that

If two solids are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

Let

x ----> the height of the larger solid in mm

y ----> the height of the smaller solid in mm

z ---> the scale factor

$z=\frac{x}{y}$

we have

$x=4\ mm\\y=3\ mm$

substitute

$z=\frac{4}{3}$ ---> scale factor

step 2

Find the volume of the larger solid

we know that

If two solids are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

x ----> the volume of the larger solid in cubic millimeters

y ----> the volume of the smaller solid in in cubic millimeters

z ---> the scale factor

$z^3=\frac{x}{y}$

we have

$z=\frac{4}{3}$

$y=250\ mm^3$

substitute the values

$(\frac{4}{3})^3=\frac{x}{250}$

solve for x

$(\frac{64}{27})=\frac{x}{250}$

$x=250(\frac{64}{27})$

$x=592.6\ mm^3$

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3 years ago

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Pani-rosa [81]

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1x20=20

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