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Alenkinab [10]
3 years ago
15

The square of p varies inversely as q. When q=

Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0

Step-by-step explanation:

Substitute known values of P and Q to solve for k: ... If A varies jointly with b and h and A=6 when b=2 and h=9, find b when A=7 and h=3. ... 140 pounds per square foot, find the volume when the pressure is 185 pounds per square foot

sorry all i got

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Ii s possible to help me pls!
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Yes but I can’t really see it

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Find the area of AAOB<br> 9√3 un²<br> 3√3 un²<br> 4.5√3 un
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Answer:

Step-by-step explanation:

The area of the equilateral triangle is \frac{\sqrt{3}}{4}(6)^{2}=\boxed{9\sqrt{3}}

7 0
2 years ago
decompose the mixed number 2 4/5
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2 \frac{4}{5}

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\frac{14}{5}

hope it's helpful ❤❤❤

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7 0
2 years ago
A zip line starts on a platform that is 404040 meters above the ground. The anchor for the zip line is 198198198 horizontal mete
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4 0
3 years ago
Read 2 more answers
Find the length of the third side. If necessary, round to the nearest tenth
Lilit [14]

\huge\bold{Given:}

Length of the base = 8

Length of the hypotenuse = 17

\huge\bold{To\:find:}

The length of the third side ''x".

\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

\longrightarrow{\purple{x\:=\: 15}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

Using Pythagoras theorem, we have

(Perpendicular)² + (Base)² = (Hypotenuse)²

\longrightarrow{\blue{}} {x}^{2} + (8)² = (17)²

\longrightarrow{\blue{}} {x}^{2} + 64 = 289

\longrightarrow{\blue{}}  {x}^{2} = 289 - 64

\longrightarrow{\blue{}}  {x}^{2} = 225

\longrightarrow{\blue{}}  x = \sqrt{225}

\longrightarrow{\blue{}}  x = 15

Therefore, the length of the missing side x is 15.

\huge\bold{To\:verify :}

\longrightarrow{\green{}} (15)² + (8)² = (17)²

\longrightarrow{\green{}} 225 + 64 = 289

\longrightarrow{\green{}} 289 = 289

\longrightarrow{\green{}} L.H.S. = R. H. S.

Hence verified.

\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{♨}}}}}

3 0
2 years ago
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