Write an equation system based on the problem. For an instance, x represents the number of $3 tickets sold and y represents the number of $5 tickets sold.
x + y = 40
3x + 5y = 136
Solve the equation system using elimination method. Use elimination of y in order to find the value of x
x + y = 40 (multiplied by 5)
3x + 5y = 136 (multiplied by 1)
-----------------------------------------
5x + 5y = 200
3x + 5y = 136
------------------ -
2x = 64
x = 64/2
x = 32
The value of x is 32. She sold 32 tickets worth $3
Lets write this out:-
2.4 + 0.8 =______ - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___
So to solve d blanks we will do d following:-
2.4 + 0.8 = 3.2
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = _____+ 1.21=_____+1.78=_____- 5.14=___
Now lets solve again:-
3.2 - 0.06 = 3.14
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21=_____+1.78=_____- 5.14=___
Now lets solve again:-
3.14 + 1.21= 4.25
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78=_____- 5.14=___
Now lets solve again:-
4.25 +1.78= 6.03
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14=___
Now lets solve again:-
6.03 - 5.14 = 0.89
Now lets write this out AGAIN.
2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89
So, 2.4 + 0.8 = 3.2 - 0.06 = 3.14 + 1.21 = 4.25 +1.78= 6.03 - 5.14= 0.89
Hope I helped ya!! xD
Answer:
b. A driver with an 8-minute commute
d. A bicyclist with a 6-minute commute
Step-by-step explanation:
X = driver to work time (Normal)
![\mu_x = 30](https://tex.z-dn.net/?f=%5Cmu_x%20%3D%2030)
![\sigma _x = 6](https://tex.z-dn.net/?f=%5Csigma%20_x%20%3D%206)
![Z_x = \frac{x- \mu}{\sigma}](https://tex.z-dn.net/?f=Z_x%20%3D%20%5Cfrac%7Bx-%20%5Cmu%7D%7B%5Csigma%7D)
![= \frac{x-30}{6}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bx-30%7D%7B6%7D)
Y = bicycle to work time (Normal)
![\mu_y = 30](https://tex.z-dn.net/?f=%5Cmu_y%20%3D%2030)
![\sigma _y = 8](https://tex.z-dn.net/?f=%5Csigma%20_y%20%3D%208)
![Z_y = \frac{y- \mu}{\sigma}](https://tex.z-dn.net/?f=Z_y%20%3D%20%5Cfrac%7By-%20%5Cmu%7D%7B%5Csigma%7D)
![= \frac{y-30}{8}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7By-30%7D%7B8%7D)
<u>Driving</u>
1) If x = 45
![Z_x = \frac{45- 30}{6}\\\\=2.50](https://tex.z-dn.net/?f=Z_x%20%3D%20%5Cfrac%7B45-%2030%7D%7B6%7D%5C%5C%5C%5C%3D2.50)
ii) If x = 8
![Z_x = \frac{8- 30}{6}\\\\=-3.67](https://tex.z-dn.net/?f=Z_x%20%3D%20%5Cfrac%7B8-%2030%7D%7B6%7D%5C%5C%5C%5C%3D-3.67)
<u>Bicycle</u>
i) If y = 44
![Z_y = \frac{44- 30}{8}\\\\=1.75](https://tex.z-dn.net/?f=Z_y%20%3D%20%5Cfrac%7B44-%2030%7D%7B8%7D%5C%5C%5C%5C%3D1.75)
ii) If y = 6
![Z_x = \frac{6 - 30}{8}\\\\=-3.00](https://tex.z-dn.net/?f=Z_x%20%3D%20%5Cfrac%7B6%20-%2030%7D%7B8%7D%5C%5C%5C%5C%3D-3.00)
The event at driving commute time x = 8 and time bicycle y = 6 are the most unusual time. this is because they are 3 standard deviation below the mean time of respective events
- driver with an 8-minute commute
- A bicyclist with a 6-minute commute
Sample amples plmas and that’s about it lol
Answer:
Question is is the A Question 2 is C Question 3 is B and Question 4 is D
Step-by-step explanation:
I hope this helped you understand ratios a little