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Natali5045456 [20]

3 years ago

6

Which of the following ordered pair are equal. a) (6,2) and (2,6)

1 answer:

Gwar [14]3 years ago

4 0

First one because thats simple

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susan designed a circular pool with a diameter of 24 meters. what is the area of the bottom of the pool?

Gennadij [26K]

Diameter = 24 m

radius = diameter/2 = 24 m / 2 = 12 m

area = pi * r^2 = 3.14 * (12 m)^2 = 3.14 * 144 m^2 = 452.16 m^2

7 0

3 years ago

The system of equations graphed below has how many solutions? y= 2x+2, y=2x

Art [367]

Y = 2x + 2
Y = 2x -
Subtract

0 = 2

This makes no sense meaning the lines are parallel. Therefore there are 0 solutions.

8 0

4 years ago

Read 2 more answers

I need Geometry help

Anvisha [2.4K]

Yes that is correct
answer
AAS congruence theorem
<M = <P
<MNR = <PNQ
RN = NQ

3 0

3 years ago

PLS help i rly need help ive posted with no help im rly confused

vesna_86 [32]

Asked and answered elsewhere.
brainly.com/question/8666894

8 0

3 years ago

lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

$x^4+95x^2 -500=0$

Substituting $x^2=a,$ given bi-quadratic equation reduces in the form of following quadratic equation:

$a^2 +95a -500=0\\$

Let us factorize the above quadratic equation:

$a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\$

Since square root of a negative number cannot be found, so:

$x \neq \pm \sqrt{-100}\\$

$CASE\: (2)\:\\When\: a =5 \implies x^2 =5\\\therefore x=\pm \sqrt{5}\\$

3 0

3 years ago