If the diameter
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Total number of balls = 50
Balls numbered as multiple of 10 = 5
Balls with red dot on them = 6
Balls numbered as multiple of 10 and having red dot on them = 1 (i.e. Ball with number 40 on it)
Probability of Ball being numbered as multiple of 10 = P(T) = 5/50 = 1/10
Probability of Ball being marked by the dot = P(D) = 6/50 = 3/25
Probability of Ball being numbered as multiple of 10 and having a red dot on it = P (T ∩ D) = 1/50
The "or" ,"union" of two events can be expressed as:
P(T ∪ D) = P(T) + P(D) - P (T ∩ D)
Using the values, we get:
P(T ∪ D) =
Thus, the probability that the ball is numbered with a multiple of 10 or has a red dot is 1/5 or 0.2
Balls numbered as multiple of 10 = 5
Balls with red dot on them = 6
Balls numbered as multiple of 10 and having red dot on them = 1 (i.e. Ball with number 40 on it)
Probability of Ball being numbered as multiple of 10 = P(T) = 5/50 = 1/10
Probability of Ball being marked by the dot = P(D) = 6/50 = 3/25
Probability of Ball being numbered as multiple of 10 and having a red dot on it = P (T ∩ D) = 1/50
The "or" ,"union" of two events can be expressed as:
P(T ∪ D) = P(T) + P(D) - P (T ∩ D)
Using the values, we get:
P(T ∪ D) =
Thus, the probability that the ball is numbered with a multiple of 10 or has a red dot is 1/5 or 0.2
Answer:
The graph you have is wrong. This is the right graph.
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