I suggest learning and studying technology and the way a computer or a phone works and how it receives info. That way, you will be able to give the device something it won't handle...... I think....
The answer to your question is b☺️☺️
def is_even_number(n):
return True if n % 2 == 0 else False
while True:
number = int(input("Enter a number: "))
if number == 0:
break
else:
if is_even_number(number):
print("Even")
else:
print("Odd")
I wrote my code in python 3.8. I hope this helps.
Answer:
After running the given pseudocode the values will be:
A. A[K] = 20, A[K + 1] = 20
Explanation:
The given pseudocode appears to be applied on an array.
Let us look at the given pseudocode one by one
A[K] = 10;
This line of code assigns value 10 to the position A[K] in array
A[K+1] = 20;
This line of code assigns value 20 to the position A[K+1]
A[K] = A[K+1];
This line will assign the value at A[K+1] to A[K] which means value 20 will be assigned to A[K]
so after this line A[K] = 20
A[K+1 ] = A[K];
This line will assign the value in A[K] to A[K+1] as A[K+1] has the value 20 currently so
A[K+1] = 20
Hence,
After running the given pseudocode the values will be:
A. A[K] = 20, A[K + 1] = 20
Answer:
Specification which has little effect on the speed of a processor is cache system bus speed clock speed socket type.
