Every hexadecimal digit represents 4 bits, so the address has 128/4 = 32 digits.
A GUID (Globally Unique IDentifier) has 128 bits. They are usually written like this:
{38a52be4-9352-4<span>53e-af97-5c3b448652f0}.</span>
There are different types of guids, depending on how they are generated. The first digit of the third group reveals the type. In the example above it is 4. A type 4 guid is fully random (except of course for the 4).
Voice Over IP (VOIP) is the option that allows the transmission of voice and often video communication over the Internet.
So, this doesn't refer to mobile or other telephone communication, but rather to the Internet solely. Applications that are examples of this type of technology are Skype, Teamspeak, Ventrilo, and others. This technology is becoming better and better with each day and will probably replace phones completely in the future.
Answer:
D. RAM is volatile, which means that it must be handheld with care when removed or replaced. A hard disk is not volatile, which means that it is much more resistant to movement during removal or replacement.
Explanation:
Most RAM (random access memory) used for primary storage in personal computers is volatile memory. Volatile memory contrasts with non-volatile memory, which does not lose content when power is lost. Non-volatile memory has a continuous source of power and does not need to have its memory content periodically refreshed.
Answer:
WAN router security standard, Web services standard
Explanation:
Complete statement with blanks filled:
In general, WAN-specific standards identify specific security requirements for WAN devices. For example, the WAN router security standard explains the family of controls needed to secure the connection from the internal network to the WAN router, whereas the Web services standard identifies which controls are vital for use of Web services provided by suppliers and external partnerships.
Answer:
The required code is given below:
Explanation:
public class Minimum {
public static Comparable min(Comparable[] values) {
if (values == null || values.length == 0) {
return null;
} else {
Comparable minValue = values[0];
for (int i = 0; i < values.length; i++) {
if (values[i].compareTo(minValue) < 0) {
minValue = values[i];
}
}
return minValue;
}
}
}
