What is the slope of the line perpendicular to the line 4x-3y+12=0?
1 answer:
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Answer: cotθ
<u>Step-by-step explanation:</u>
tanθ * cos²θ * csc²θ
=
=
= cotθ
Answer: B
<u>Step-by-step explanation:</u>
The parent graph is y = x²
The new graph y = -x² + 3 should have the following:
- reflection over the x-axis
- vertical shift up 3 units
Answers:
- a. Quadrant II
- b. negative
- c.
- d. C
- e.
<u>Explanation:</u>
a) Quadrant 2 is:
b) In Quadrant 2, cos is negative and sin is positive, so tan is negative
c) =
d) the reference line is above the x-axis so it is negative -->
e)
its pithagoreon so
c^2= a^2+ b^2
c^2= 32^2 +24^2
c^2= 1,024+576
c^2= 1600
c== 40