What is the slope of the line perpendicular to the line 4x-3y+12=0?
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Answer
Length = 10 ft
Width = 5 ft
Explanation
Area of the rectangle given = 50 ft²
Let the width of the rectangle be x
So this means the length of the rectangle will be 3x - 5
What to find:
The dimensions of the rectangle.
Step-by-step solution:
Area of a rectangle = length x width
i.e A = L x W
Put A = 50, L = 3x - 5, W = x into the formula.
The quadratic equation can now be solve using factorization method:
Since the dimension can not be negative, hence the value of x will be = 5.
Therefore, the dimensions of the rectangle will be:
Answer:
The perimeter of polygon ABCD, to the nearest thousandth units is
22.227 units
The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units
The area of polygon ABCD' is 19.5 units²
Step-by-step explanation:
The coordinates forming the polygon are
A (-4,-1), B(-2,3), C(2,2), and D(4,-3)
The perimeter then is given by the sum of the length of the sides as follows;
Length of line between two X and Y points distance, xi and yj apart is
length XY =
Therefore, the length between points AB is
length AB =
= = 4.472 units
Similarly, length BC is given by
Length BC = = 4.123 units
Length CD = = 5.385 units
Length DA = = 8.246 units
The perimeter is equal to;
length AB + Length BC + Length CD + Length DA
= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units
If the point D is moved up 2 units and left 1 unit we have
D' = x-1, y+2 where x and y are the coordinates of point D
D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)
The length D'A = =7 units
The perimeter of polygon ABCD'
length AB + Length BC + Length CD + Length D'A
= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.
The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows
=
=
Triangle ABC we have
A(-4,-1)
B(-2,3)
C(2,2)
=
=
Triangle ACD'
A(-4,-1)
C(2,2)
D'(3, -1)
=
= 10.5 units²
Area of polygon = =
+
= (9 + 10.5) units²
Area of polygon ABCD' = 19.5 units².