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SIZIF [17.4K]
2 years ago
14

Reba needs to simplify the expression below. 6 1/2+3.5x2-7 divided by 3 Which operation should she perform first?

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
4 0

Answer:

mutipication

Step-by-step explanation:

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Hey can someone help?
Ronch [10]

The value of the given variable x in the missing angles is; x = 12°

<h3>How to find alternate Angles?</h3>

Alternate angles are defined as the angles that occur on opposite sides of the transversal line and as such have the same size. There are two different types of alternate angles namely alternate interior angles as well as alternate exterior angles.

Now, from the question, we can see that ∠4 and ∠6 suit the definition of alternate angles and as such we can say that they are both congruent.

Since ∠4 = (8x + 4)° and ∠6 = (6x + 28)°, then we can say that;

(8x + 4)° =  (6x + 28)°

Rearranging this gives us;

8x - 6x = 28 - 4

2x = 24

x = 24/2

x = 12°

Read more about Alternate Angles at; brainly.com/question/24839702

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4 0
1 year ago
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A circle's ___ is twice as long ad it's radius
chubhunter [2.5K]
A circles DIAMETER is twice as long as its radius

Hope this helps you :)
5 0
3 years ago
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Find the missing length of the right triangle.<br> a<br> 21<br> 35
WITCHER [35]

Answer:

28

Step-by-step explanation:

Use the pythagorean theorem and solve for a:

a² + b² = c²

a² + 21² = 35²

a² + 441 = 1225

a² = 784

a = 28

So, the missing length is 28.

4 0
3 years ago
Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).
Elan Coil [88]

Answer: \int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = \left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0

Then, replacing with point P and normal vector n:

36(x-5) + 20(y-0) + 45(z-0) = 0

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

z = \frac{180-36x-20y}{45}

When z = 0:

y = 9 + \frac{-9x}{5}

When z=0 and y=0:

x = 5

Then, triple integral is:

\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx

Calculating:

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx

\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0  {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx

\frac{1}{45} \int\limits^5_0  {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4}  } \, dx

\frac{1}{45} [30375-60750+118462.5-39150]

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0
3 years ago
A short-order cook can prepare 40 hamburgers in 30 minutes. The cook calculates a unit rate of 60 hamburgers per hour. She multi
Rus_ich [418]

Answer:

B is correct answer mark as brainliest answer

3 0
3 years ago
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