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Levart [38]
2 years ago
10

Help me out pls and thank you very much !!!!!!!

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
5 0

Answer:

8

Step-by-step explanation:

Since this is a rectangle, the opposite sides are congruent.

So the lengths of DG and EF are equal

3x + 5 = 29

3x = 29 - 5

3x = 24

x = 24/3

x = 8

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3 years ago
at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t
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The probability that a student participates in both sports and drama is 0.14.

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If A and B are any two events, then the probability of the joint event (A\cup B) is given by the following formula: P(A\cup B)=P(A)+P(B)-P(A\cap B)

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose S denotes that "a student participates in sports" and D denotes that "a student participates in drama".
So, we have P(S)=\frac{42}{100}=0.42, P(D)=\frac{25}{100}=0.25, P(S\cup D)=\frac{53}{100}=0.53.

We want to find the probability that a student participates in both sports and drama i.e., we want to find P(S\cap D).

By the above formula, we obtain:

P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}

Therefore, the probability that a student participates in both sports and drama is 0.14.

To learn more about probability, refer: brainly.com/question/24756209

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