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4 years ago

12

a cylindrical tank has a diameter of 5 feet and the distance between the circular bases is 6 feet. find the lateral area of the

tank.

1 answer:

Vitek1552 [10]4 years ago

3 0

Answer: Can we see a picture

Step-by-step explanation:

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Write the first 4 terms of the sequence defined by the given rule f(n)=n2 -1

Softa [21]

Answer:

<h2>0, 3, 8, 15</h2>

Step-by-step explanation:

Substitute n = 1, n = 2, n = 3 and n = 4 to the equation f(n) = n² - 1:

f(1) = 1² - 1 = 1 - 1 = 0

f(2) = 2² - 1 = 4 - 1 = 3

f(3) = 3² - 1 = 9 - 1 = 8

f(4) = 4² - 1 = 16 - 1 = 15

5 0

3 years ago

Given a function I and a subset A of its domain, let I(A) represent the range of lover the set A; that is, I(A) = {I(x) : x E A}

Ede4ka [16]

Step-by-step explanation:

(a)

Using the definition given from the problem

$f(A) = \{x^2 \, : \, x \in [0,2]\} = [0,4]\\f(B) = \{x^2 \, : \, x \in [1,4]\} = [1,16]\\f(A) \cap f(B) = [1,4] = f(A \cap B)\\$

Therefore it is true for intersection. Now for union, we have that

$A \cup B = [0,4]\\f(A\cup B ) = [0,16]\\f(A) = [0,4]\\f(B)= [1,16]\\f(A) \cup f(B) = [0,16]$

Therefore, for this case, it would be true that $f(A\cup B) = f(A)\cup f(B)$ .

(b)

1 is not a set.

(c)

To begin with

$A\cap B \subset A,B$

Therefore

$g(A\cap B) \subset g(A) \cap g(B)$

Now, given an element of $g(A) \cap g(B)$ it will belong to both sets, therefore it also belongs to $g(A\cap B)$ , and you would have that

$g(A)\cap g(B) \subset g(A \cap B)$ , therefore $g(A)\cap g(B) = g(A \cap B)$ .

(d)

To begin with $A,B \subset A \cup B$ , therefore

$g(A) \cup g(b) \subset g(A\cup B)$

7 0

3 years ago

The points (3,9) and (-3,-9) are plotted on the coordinate plane using the equation y= a•x. What is the value of a?

8_murik_8 [283]

A=3

The equation y=3x goes through both points

Hope I helped

5 0

3 years ago

The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 – 5t2, where t is the tim

Nostrana [21]

Answer:

$\sqrt{2}$ - 1

Step-by-step explanation:

h = 20 – 5t2 = 15 -> t = 1

h = 20 – 5t2 = 10 -> t = $\sqrt{2}$

interval $\sqrt{2}$ - 1

8 0

3 years ago

Read 2 more answers

??????<br> What's this one

Soloha48 [4]

The closest distance is C. 12 feet

7 0

3 years ago