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user100 [1]
3 years ago
4

What is one step taken when solving a computer software problem? making sure the power cord is plugged in properly scanning the

computer and deleting any viruses searching for any spills or damage to the computer taking a look at all the cables and connectors when students have computer trouble they usually are expected to make any simple fixes on their own. solve complex issues by themselves. drop their school work until it is resolved. pay a technician a high fee to fix the issue.
Engineering
1 answer:
Aleks04 [339]3 years ago
5 0

Answer:

<u>Answer: B) Scanning the computer and deleting any viruses.</u>

Explanation:

<em>Some of the feedback I hear from new developers working on a programming problem revolves around uncertainty of where to start. You understand the problem, the logic, basics of the syntax, etc. If you see someone else’s code or have someone to guide you, you can follow along. But maybe you feel uncertain about doing it yourself and have trouble turning your thoughts into code at first even though you understand the syntax or logic. Here’s my process and some tips to tackling a sample problem that hopefully some of you may find helpful in your journey. </em>

<em />

<em>If you need further expenation then:</em>

<em>Some of the feedback I hear from new developers working on a programming problem revolves around uncertainty of where to start. You understand the problem, the logic, basics of the syntax, etc. If you see someone else’s code or have someone to guide you, you can follow along. But maybe you feel uncertain about doing it yourself and have trouble turning your thoughts into code at first even though you understand the syntax or logic. Here’s my process and some tips to tackling a sample problem that hopefully some of you may find helpful in your journey.</em>

<em />

<em>May i please have brainliest</em>

<em> </em>

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What are the advantages and disadvantages of each type of structure?
allsm [11]

Answer:

It organization structure an advantage. Disadvantage is employees are responsible for the project team.

Explanation:

One advantage of the matrix organizational structure is that people across different functional areas have a better understanding of their coworkers in other areas.

A disadvantage is that employees are responsible of their project team as well as to hair functional areas. It can create some conflict.

6 0
3 years ago
Consider a turbojet powered airplane flying at a standard altitude of 30,000ft at a velocity of 500 mph. The turbojet engine its
grandymaker [24]

Answer:

T  = 20.42 N

Explanation:

given data

standard altitude = 30,000 ft

velocity Ca = 500 mph = 0.4 m/s

inlet areas Aa = 7 ft² = 0.65 m²

exit areas Aj = 4.5 ft²  =  0.42 m²

velocity at exit Cj = 1600 ft/s = 487.68 m/s

pressure exit \rhoj = 640 lb/ft²   = 0.3 bar

solution

we get here thrust of the turbojet that is  express as

thrust of the turbojet T = Mg × Cj - Ma × Ca + ( \rhoj Aj - \rhoa Ag )   .............1

here Ma = Mg

Ma = \rhoa × Ca Aa = 0.042 kg/s

put value in equation 1 we get

T = 0.042 × (487.68 -0.14) + ( 0.3 ×  - 0.3 × 0.65 )  

T  = 20.42 N

5 0
3 years ago
A diesel engine with CR= 20 has inlet at 520R, a maximum pressure of 920 psia and maximum temperature of 3200 R. With cold air p
Stella [2.4K]

Answer:

Cut-off ratio\dfrac{V_3}{V_2}=6.15

Cxpansion ratio\dfrac{V_4}{V_3}=3.25

The exhaust temperatureT_4=1997.5R

Explanation:

Compression ratio CR(r)=20

\dfrac{V_1}{V_2}=20

P_2=P_3=920 psia

T_1=520 R ,T_{max}=T_3,T_3=3200 R

We know that for air γ=1.4

If we assume that in diesel engine all process is adiabatic then

\dfrac{T_2}{T_1}=r^{\gamma -1}

\dfrac{T_2}{520}=20^{1.4 -1}

T_2=1723.28R

\dfrac{V_3}{V_2}=\dfrac{T_3}{T_2}

\dfrac{V_3}{V_2}=\dfrac{3200}{520}

So cut-off ratio\dfrac{V_3}{V_2}=6.15

\dfrac{V_1}{V_2}=\dfrac{V_4}{V_3}\times\dfrac{V_3}{V_2}

Now putting the values in above equation

\dfrac20=\dfrac{V_4}{V_3}\times 6.15

\dfrac{V_4}{V_3}=3.25

So expansion ratio\dfrac{V_4}{V_3}=3.25.

\dfrac{T_4}{T_3}=(expansion\ ratio)^{\gamma -1}

\dfrac{T_3}{T_4}=(3.25)^{1.4 -1}

T_4=1997.5R

So the exhaust temperatureT_4=1997.5R

3 0
4 years ago
The output S/N at thereceiver must be greater than 40 dB. The audio signal has zero mean, maximum amplitude of 1, power of ½ Wan
abruzzese [7]

Given that,

The output signal at the receiver must be greater than 40 dB.

Maximum amplitude = 1

Bandwidth = 15 kHz

The power spectral density of white noise is

\dfrac{N}{2}=10^{-10}\ W/Hz

Power loss in channel= 50 dB

Suppose, Using DSB modulation

We need to calculate the power required

Using formula of power

P_{L}_{dB}=10\log(P_{L})

Put the value into the formula

50=10\log(P_{L})

P_{L}=10^{5}\ W

For DSB modulation,

Figure of merit = 1

We need to calculate the input signal

Using formula of FOM

FOM=\dfrac{\dfrac{S_{o}}{N_{o}}}{\dfrac{S_{i}}{N_{i}}}

1=\dfrac{\dfrac{S_{o}}{N_{o}}}{\dfrac{S_{i}}{N_{i}}}

\dfrac{S_{i}}{N_{i}W}=\dfrac{S_{o}}{N_{o}}

Put the value into the formula

\dfrac{S_{i}}{2\times10^{-10}\times15\times10^{3}}

\dfrac{S_{i}}{30\times10^{-7}}

S_{i}

S_{i}=30\times10^{-3}

We need to calculate the transmit power

Using formula of power transmit

S_{i}=\dfrac{P_{t}}{P_{L}}

P_{t}=S_{i}\times P_{L}

Put the value into the formula

P_{t}=30\times10^{-3}\times10^{5}

P_{t}=3\ kW

We need to calculate the needed bandwidth

Using formula of bandwidth for DSB modulation

bandwidth=2W

Put the value into the formula

bandwidth =2\times15

bandwidth = 30\ kHz

Hence, The transmit power is 3 kW.

The needed bandwidth is 30 kHz.

3 0
3 years ago
Bài 3: Cho cơ cấu culít (hình 3.5) với các kích thước động lAB = 0,5lAC = 0,1m. Khâu 3 chịu tác dụng của mô men M3 = 500 N. Cơ c
lesya [120]
??????????????????????
3 0
3 years ago
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