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Doss [256]
3 years ago
8

Given a manhole with the outlet invert elevation of 2605. A run of 48 inch pipe connects to the next manhole at an invert elevat

ion of 2610. What is the distance between manholes if the correct pipe grade is 3%
Engineering
1 answer:
alexdok [17]3 years ago
5 0

Answer:

Distance between manholes = 166.67 (Unit) (Approx)

Explanation:

Given:

Invert elevation = 2605

New Invert elevation = 2610

Grade % = 3% = 0.03

Find:

Distance between manholes

Computation:

Grade % = (Change in elevation)/Distance between objects

0.03 = (2610-2605)/Distance between manholes

0.03 = 5 / Distance between manholes

Distance between manholes = 166.67 (Unit) (Approx)

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Answer:

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A cylindrical rod of a metal alloy is stressed elastically in tension. The original diameter was 11 mm and a force of 55 kN was
andrey2020 [161]

Answer:

10.984mm

Explanation:

by elastic modulus

stress=modulus of elasticity*strain

stress=loading/area                          area" cross-section"

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convert MPa and GPa to pascal.

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v=Poisson  ratio

lateral strain=(-v)*axial strain= -0.31*0.00463

lateral strain= -1.4353*10^-3=change in diameter/ original diameter

change in diameter=(-1.4353*10^-3)*0.011= -1.57883*10^-5 m

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Basile [38]

Answer:

(b) False

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So it is false statement as internal energy is not a path function

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likoan [24]

Answer:

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Explanation:

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