Given a manhole with the outlet invert elevation of 2605. A run of 48 inch pipe connects to the next manhole at an invert elevat
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Answer:
17.658 kPa
Explanation:
The hydrostatic pressure of a fluid is the weight of a column of that fluid divided by the base of that column.
Also, the weight of a column is its volume multiplied by it's density and the acceleration of gravity:
Meanwhile, the volume of a column is the area of the base multiplied by the height:
Replacing:
The base cancels out, so:
The pressure depends only on the height of the fluid column, the density of the fluid and the gravity.
If you have two point at different heights (or depths in the case of objects submerged in water) each point will have its own column of fluid exerting pressure on it. Since the density of the fluid and the acceleration of gravity are the same for both points (in the case of hydrostatics density is about constant for all points, it is not the case in the atmosphere), we can write:
We do not know at what depth the man of this problem is, but it doesn't matter, because we know the difference in height of the two points of interes (h1 - h2) = 1.8 m. So: