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kumpel [21]
2 years ago
11

Which of the following is an extraneous solution of StartRoot 4 x + 41 EndRoot = x + 5? x = –8 x = –2 x = 2 x = 8

Mathematics
2 answers:
larisa [96]2 years ago
8 0

Answer:

A

Step-by-step explanation:

took test

Finger [1]2 years ago
5 0

Answer:

-8

Step-by-step explanation:

when you solve for x you get -8 but when you pkug it back in both sides are not equal, making it extranious

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tankabanditka [31]

Answer:

Step-by-step explanation:

hello,

i advice you check the question again if it is GF(2^{4}) or GF(24). i believe the question should rather be in this form;

multiplication in GF(2^{4}): Compute A(x)B(x) mod P(x) = x^{4} + x+1, where A(x)=x^{2}+1, and B(x)=x^{3} + x+1.

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)=(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1  ) = (x^{5} +x^{3}+x^{2}  ) + (x^{3}+x+1  ) mod (x^{4} + x+1 )

= x^{5}+2x^{3} +x^{2}  + x + 1 mod(x^{4}+x+1  )

=2x^{2} +1

please note that the division by the modulus above we used

\frac{x^{5}+2x^{3}+x^{2} +1  }{x^{4}+x+1}= x+\frac{2x^{3} +1}{x^{4}+x+1}

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yanalaym [24]

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Step-by-step explanation:

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