From the given dimensions, of MI, IN, NT, TM, and MN, the quadrilateral
MINT can be drawn as shown in the attached image.
<h3>What are the steps for the construction of MINT?</h3>
The given dimensions of the quadrilateral MINT are;
MI = 5 cm
IN = 6 cm
NT = 7 cm
TM = 3 cm
MN = 9 cm
The side MN is a diagonal of MINT, therefore;
ΔMIN, and ΔMTN are triangles with a common base = MN
The steps to construct MINT are therefore;
- Step 1; Draw the line MN = 9 cm.
- Step 2; Place the compass at point <em>M</em> and with a radius MI = 5 cm, draw an arc on one side of MN.
- Step 3; Place the compass at <em>N</em> and with radius IN = 6 cm, draw an arc to intersect the arc dawn in step 1 above.
- Step 4; Place an arc at point <em>M</em> and with radius TM = 3 cm draw an arc on the other side of MN.
- Step 5; Place the compass at point <em>N</em> and with radius NT = 7 cm, draw an arc to intersect the arc drawn in step 3.
- Step 6; Join the point of intersection of the arcs to points <em>M</em> and <em>N</em> to complete the quadrilateral MINT.
Please find attached the drawing (showing the construction arcs) of the
quadrilateral MINT created with MS Word.
Learn more about types of geometric construction here:
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Answer:
In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q. Since q may be equal to 1, every integer is a rational number. The set of all rational numbers, often referred to as "the rationals", the field of ... The decimal expansion of a rational number either terminates after a finite
Step-by-step explanation:
Answer:
x = 1/3
Step-by-step explanation:
Move all terms containing x to the left side of the equation.
8+6x=10
Move all terms not containing x to the right side of the equation
6x=2
Divide each term by 6 and simplify.
Exact Form:
x=1/3
Decimal Form:
x=0.3333333333
Hope this helps!
Answer: The answers are
(i) The slope of segments DE and AC is not 0.
(ii) The coordinates of D and E were found using the Midpoint Formula.
Step-by-step explanation: We can easily see in the proof that the co-ordinates of D and E were found using the mid-point formula, not distance between two points formula. So, this is the first flaw in the Gina's proof.
Also, we see that the slope of line DE and AC, both are same, not equal to 0 but is equal to

which is 0 only if 
So, this is the second mistake.
Thus, the statements that corrects the flaw in Gina's proof are
(i) The slope of segments DE and AC is not 0.
(ii) The coordinates of D and E were found using the Midpoint Formula.