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alexandr1967 [171]
3 years ago
15

A customer wants to enlarge a photo to 2.75 it’s current height the photo current height is 3.25 inches what should its enlarged

height be in inches
Mathematics
1 answer:
raketka [301]3 years ago
4 0

Answer:

8.9375

Step-by-step explanation:

2.75×3.25=8.9375

According to the question it said <u>i</u><u>n</u><u>c</u><u>r</u><u>e</u><u>a</u><u>s</u><u>e</u><u> </u><u>to</u><u> </u>and that is why I only multiplied but if the question said <u>increase</u><u> </u><u>by</u><u> </u>then I would have to add my product (8.9375) to the original height of the photo.

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Solve 5x^2 − 3x + 17 = 9.
Vedmedyk [2.9K]

Answer:

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = \frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}

or

x = \frac{3\pm\sqrt{9-160}}{10}

or

x = \frac{3+\sqrt{-151}}{10} and x = \frac{3-\sqrt{-151}}{10}

or

x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

here i = √(-1)

Hence,

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

7 0
3 years ago
In the triangle below, what is the approximate value of x?
Allushta [10]

Answer:

hi

apply BPT

\frac{4}{18}  =  \frac{x}{22}

solve it now

x = 88/18 approx = 4.9 inches

3 0
2 years ago
Determine the slope, if it exists, of the graph of the linear equation y=3.1x-3
Sunny_sXe [5.5K]
Slope = 3.1

This is in y =mx + b

Where m = slope
6 0
3 years ago
Read 2 more answers
part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.​
andreev551 [17]

Answer:  \bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c²  , <em>where "c" is the hypotenuse</em>

5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}

Note: (15)² + (3√11)² = hypotenuse²   →   hypotenuse = 18

6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}

Note: 8² + 15² = hypotenuse²   →   hypotenuse = 17

7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}

Note: hypotenuse not needed for tan

8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}

Note: 2² + 6² = hypotenuse²   →   hypotenuse = 2√10

8 0
3 years ago
use the table to find each ratio 8 white socks and 6 black socks and 4 blue socks and 5 brown socks ... white socks to brown soc
nevsk [136]
<h3>Answer:</h3>
  • white : brown = 8 : 5
  • black : total = 6 : 23
<h3>Explanation:</h3>

Each of the ratio components (white socks, brown socks, black socks, total socks) has an associated number (8, 5, 6, 23). Write the desired ratio using the associated numbers.

8 0
3 years ago
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