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11Alexandr11 [23.1K]
3 years ago
10

Paula purchase 3 dvd and 7 cds and spent between 90 and 100. Each dvd costs the same amount the price of cd is 10 select all amo

unts that could be the price of the dvd
Mathematics
1 answer:
sveticcg [70]3 years ago
3 0

The options aren't given, however, the range of amount spent could be calculated

Answer:

Kindly check explanation

Step-by-step explanation:

Paula purchase 3 dvd and 7 cds and spent between 90 and 100. Each dvd costs the same amount the price of cd is 10 select all amounts that could be the price of the dvd

Given that :

DVD costs the same amount

Number of DVD's = 3

Cost of cds = 10

Number of cds = 7

Total cost of cd's = 10 * 7 = 70

Let the price of DVD = x

Total amount spent = 90 - 100

Lowest price of DVD :

(amount spent - price of cd) / number of dvd

(90 - 70) / 3 = 20 /3 = 6.667

Highest price :

(100 - 70) / 3 = 30 / 3 = 10

Hence the pice of each DVD will range between /

6.6666 and 10.

Hence, prices listed within the range above are possible.

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3 years ago
Need Answered ASAP
kicyunya [14]

Answer:

The possible rational roots are: +1, -1 ,+3, -3, +9, -9

Step-by-step explanation:

The Rational Root Theorem tells us that the possible rational roots of the polynomial are given by all possible quotients formed by factors of the constant term of the polynomial (usually listed as last when written in standard form), divided by possible factors of the polynomial's leading coefficient. And also that we need to consider both the positive and negative forms of such quotients.

So we start noticing that since the leading term of this polynomial is x^3, the leading coefficient is "1", and therefore the list of factors for this is: +1, -1

On the other hand, the constant term of the polynomial is "9", and therefore its factors to consider are: +1, -1 ,+3, -3, +9, -9

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And therefore, this is the list of possible roots of the polynomial.

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Name the intersection of plane bpq and plane cpq. 1) the planes do not intersect. 2) bp 3)pq 4)cq
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Imagine two planes: they can be parallel or not. If they are parallel, then they don't have common points, but your planes have common points P and Q.

So, you can conclude that these two planes are not parallel, then they should intersect. Two planes intersect <span>in a straight line and this line consists of all common points of both planes.
</span>
If planes are named BPQ (points B, P, Q do not lie on one straight line) and CPQ (points C, P, Q do not lie on one straight line), you can see two common points P and Q. Hence the intersection line must contain these two points and may be named as PQ (and points B and C do not lie on this line).

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