Step 1: Create an equation with a slope of 6
y=6x+b
Step 2: Substitute x and y by with the point (1,2) and solve the equation for b
y=6x+b
2=6(1)
2=6
2=6+b
b=-4
Step 3: Substitute -4 for b in the equation
y=6x+b
y=6x+(-4)
y=6x-4
The equation that has a slope of 6 and passes through the point (1,2) in point-slope form:
y=6x-4
Pretty sure it’s “b= p/2 - a” which is the second answer
I am not sure what's questions you wanted me to answer but the answer to number 17 is 13
Answer: Option D.
Step-by-step explanation:
this is a quadratic equation of the form:
y = ax^2 + bx + c
First, things you must see.
The graph opens up, so we must have thata a is greater than zero, so we can discard the first option.
Second, we can see that the vertex is located in x ≈ 70
The vertex of a quadratic equation is: x = -b/2a
so we have:
70 = -b/2a
let's try our options and see if we can discard other:
B:
-b/2a = 69.9/2 = 34.95
we can discard this option.
C:
-b/2a = 78/2 = 39 we can discard this option.
D:
-b/2a = 69.9/2*0.5 = 69.9
This is the only one that fits, so this is the correct option.
