1.rivers and streams
2.seepage from the ground
idk sry I don’t want to give u wrong answer
Answer:
- What percent of the population is BB? (Round to two decimal places) → 17% BB
- What percent of the population is Bb? (Round to two decimal places) → 48% Bb
- What percent of the population is bb? (Round to two decimal places) → 35% bb
- What is the frequency of the single dominant allele B? (Round to two decimal places) → 0.41
- What is the frequency of the single recessive allele b? (Round to two decimal places) → 0.59
Explanation:
Due to technical problems, you will find the complete answer and explanation in the attached files
Answers and Explanation:
Find enclosed the Punnet square.
T= dominant allele
t= recessive allele
Tt= heterozygous genotype
TT and tt= homozygous genotype
- The male pea plant's genotype is Tt (heterozygous)
- The female pea plant's genotype is Tt (heterozygous)
- Male gametes: T and t
- Female gametes: T and t
- The expected genotypic ratio of the offpring will be:
TT: Tt: tt ⇒ 1: 2: 1
1/4 of the offpring will be TT genotype (dominant homozygous), 1/2 of the offpring will be Tt (heterozygous) genotype and 1/4 of the offpring will be tt genotype (recessive homozygous).
- The expected phenotypic ratio of the offpring will be:
tall : short ⇒ 3 : 1
3/4 of the offpring will be tall (TT and Tt) and the restant 1/4 will be short (tt).