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DIA [1.3K]
3 years ago
10

What is the equation of the line that passes through the point (2,7) and has a slope of 6?

Mathematics
1 answer:
BARSIC [14]3 years ago
8 0

Answer <u>(assuming it can be in point-slope form)</u>:

y-7 = 6(x-2)    

Step-by-step explanation:

Use the point-slope formula y-y_1 = m (x-x_1) to write the equation of the line in point-slope form. All you need to do is substitute m, x_1, and y_1 for real values.

Since m represents the slope, substitute 6 in its place. Since x_1 and y_1 represent the x and y values of one point the line intersects, take the x and y values of (2,7) and substitute them into the formula as well. So, substitute 2 for x_1 and 7 for y_1. This gives the following equation and answer:

y-7 = 6(x-2)

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Plsssssss can someone help me
77julia77 [94]

Answer:

2^3 = 8

Step-by-step explanation:

2*2*2 = 8

16 - 8 = 8

8 / 2 = 4

4 + 9 = 13

13 may be your answer

5 0
2 years ago
Read 2 more answers
Solve for y. <br><br> 3y – 12 = –30 A. –6 B. 32 C. –2 D. 2
kogti [31]
3y-12=-30
3y=-30+12
3y=-18
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y=-6.
Answer: A. 
6 0
3 years ago
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A survey of 700 adults from a certain region​ asked, "What do you buy from your mobile​ device?" The results indicated that 59​%
Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are  (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes n_{1} = 400 and n_{2} = 300

Proportion of mean p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52

<u>Null hypothesis H0</u> : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

<u>Alternative hypothesis H1:</u>- p1 ≠ p2

a) The test statistic is

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }

where p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}  

on calculation we get   p = 0.56    

now q =1-p = 1-0.56=0.44

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }\\   =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300}   }

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

<u>conclusion</u>:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) <u>95% confidence intervals</u>

The confidence intervals are P± 1.96(√PQ/n)

we know that = p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of <u>confidence intervals  (0.523 ,0.596)</u>

<u></u>

3 0
3 years ago
Pls solve this qn..............ASAP<br> PLS DON'T SPAMMMMM!!
Anni [7]

Probability ( a flowering plant or fruit plant) is  \frac{13}{30} and Probability (neem plant or peepal plant) is  \frac{29}{60}.

Step-by-step explanation:

Given,

Number of neem plant = 125

Number of peepal plant = 165

Number of creppers plant = 50

Number of fruit plant = 150

Number of flowering plant = 110

To find the probability ( a flowering plant or fruit plant)

and probability ( neem or peepal)

Formula

P( A or B) = P(A) + P(B)

Probability ( a flowering plant or fruit plant) = \frac{110}{600} + \frac{150}{600}

= \frac{260}{600} = \frac{13}{30}

And,

Probability (neem plant or peepal plant) = \frac{125}{600} +\frac{165}{600}

= \frac{290}{600} = \frac{29}{60}

4 0
3 years ago
Ab= 6cm Ac=12cm <br> Calculate the length of Ad <br> Give your answer to 3 significant figures
Allisa [31]

Answer:

12.686cm

Step-by-step explanation:

By using pythagoras, we can find CB.

We know that a^2+b^2=c^2

Therefore, 12^2-6^2=CB^2

CB=\sqrt{108} (it has to be positive since it is distance)

now we look at triangle BCD and use SOH CAH TOA.

Sin55=CB/CD\\Therefore, CD= 12.686

8 0
3 years ago
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