What is the answer someone help meeee

If QR=x+29 and PS=x–16, what is the value of x?

Juli2301 [7.4K]

Answer:

61

Step-by-step explanation:

PS is a midsegment of the triangle, so is half the length of the parallel base segment.

2PS = QR

2(x -16) = x +29 . . . . . substitute given expressions

2x -32 = x +29 . . . . . eliminate parentheses

x = 61 . . . . . . . . . . . . add 32-x

6 0

2 years ago

A line with a slope of -4 passes through the point

Viktor [21]

Answer:

y = -4x - 22

Step-by-step explanation:

m = -4

using (-6,2)

Slope-intercept: y = mx + b

2 = -4(-6) + b

2 = 24 + b

b = -22

y = -4x - 22

4 0

2 years ago

What is the classification of a triangle with side lengths of 10, 10, and 9?

kotykmax [81]

B.Acute triangle
You have to square all three numbers which would be 100, 100, and 81. The next step is adding the two shortest sides, which would be 100 & 81. The sum of those two sides add up to 181. If the sum is greater than the 3rd side squared than it would be acute. If the sum and the third side squared were equal it would be a right triangle. If the 3rd side squared was greater than the sum of the two sides squared it would be obtuse

6 0

3 years ago

Section 5.2 Problem 6: Find the general solution <img src="https://tex.z-dn.net/?f=y%27%27%20%2B%206y%27%20%2B%2010y%2

mihalych1998 [28]

Answer:

$y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Step-by-step explanation:

Given Second-Order Homogenous Differential Equation

$y''+6y'+10y=0$

Use Auxiliary Equation

$m^2+6m+10=0\\\\(m+3)^2+1=0\\\\(m+3)^2=-1\\\\m+3=\pm i\\\\m=-3\pm i$

General Solution

$y=e^{pt}(A\: cos\: qt+B\:sin\:qt)\\\\y=e^{-3t}(A\: cos\: t+B\:sin\:t)$

Note that the DE has two distinct complex solutions $p\pm qi$ where $A$ and $B$ are arbitrary constants.

4 0

2 years ago

Trains headed for destination A arrive at the train station at 15-minute intervals starting at 7:00 am, whereas trains headed fo

maks197457 [2]

Answer:

The answer to the question is 0.43. Let's explain why.

Step-by-step explanation:

A train arrives at the station at 15-minute intervals starting from 7:00 am which makes the train arrives at;

7:00

7:15

7:30

7:45

8:00

B train arrive at 12-minute intervals starting at 7:07 means B train arrives at;

7:07

7:19

7:31

7:43

7:55

Now, let's review the chances of a passenger arrives at the station any time between 7:00 am and 8:00 am

If the passenger arrives between 7:00 - 7:07 the passenger will get into B train which gives us the $\frac{7}{60}\\$ chance since an hour is 60 minutes and the passenger waited for 7 minutes.
If the passanger arrives between 7:07 - 7:15 passenger will get into A train which gives $\frac{8}{60}$ chance. If we apply this to the time limits it goes by;
Between 7:15 - 7:19 passenger will go to B destination which gives $\frac{4}{60}$ chance
Between 7:19 - 7:30 passenger will go to A destination means $\frac{11}{60}$ chance
Between 7:30 - 7:43 passenger will go to B destination means $\frac{13}{60}$ chance
Between 7:43 - 7:45 passenger will go to A destination which gives $\frac{2}{60}$ chance
Between 7:45 - 7:55 passenger will go to B destination means $\frac{10}{60}$ chance
An lastly between 7:55 - 8:00 passenger will go to A destination which gives us $\frac{5}{60}$ chance

Now for passenger to go to A destination the total chances are:

$\frac{8}{60} + \frac{11}{60} + \frac{2}{60} + \frac{5}{60} = \frac{26}{60}$ = 0.43

6 0

3 years ago