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mel-nik [20]
3 years ago
8

Edward has started up a new company with his friend, Matthew. Currently, he has only two people working with him. Which type of

network architecture do you think is appropriate for them at this point of time?
Computers and Technology
1 answer:
Kruka [31]3 years ago
6 0

A Peer-to-peer network architecture would work best for Edward and Matthew.

Although they have the option of creating a Client-Server type of network architecture, the number of people that they are currently working with would cost them a lot more than a peer-to-peer architecture.

One of the advantages of using a Peer-to-peer network architecture for a small network would be the access of files between all computers in the network. Even if one of the computers will fail, the other computers will still have access to the different files and information they will need to keep the company moving forward.

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olga_2 [115]

Answer:

111001 - 57

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1001000 - 72

:)

7 0
3 years ago
Write a method named countInRange that accepts three parameters: an ArrayList of integers, a minimum and maximum integer, and re
marissa [1.9K]

Answer:

In Java:

The method is as follows:

public static int countInRange (ArrayList<Integer> MyList, int min, int max) {  

       int count = 0;

       for (int i = 0; i < MyList.size(); i++)  {

           if(MyList.get(i)>=min && MyList.get(i)<=max){

               count++;

           }  

       }

       return count;

 }

Explanation:

This defines the method

public static int countInRange (ArrayList<Integer> MyList, int min, int max) {

This declares and initializes count to 0  

       int count = 0;

This iterates through the ArrayList

       for (int i = 0; i < MyList.size(); i++)  {

This checks if current ArrayList element is between min and max (inclusive)

           if(MyList.get(i)>=min && MyList.get(i)<=max){

If yes, increase count by 1

               count++;

           }  

       }

This returns count

       return count;

 }

To call the method from main, use:

countInRange(v,m,n)

<em>Where v is the name of the ArrayList, m and n are the min and max respectively.</em>

6 0
3 years ago
Which of the following demonstrates the proper way to specify a variable-length argument list?
larisa86 [58]

Answer:

The answer to this question is option "d".

Explanation:

In the given question option d is correct because variable-length argument is a new feature in J2SE 5.0 which stands for java 2 standard edition and 5.0 is the version name. It is the variable-length argument lists. A coder can create functions that uses a function to receive several parameter that is not specified. An argument type followed by an ellipsis(...) in the parameter list of a method means that a fixed number of arguments of that particular type is obtained by the method. and other options are not correct that can be given as:

  • In option a, we do not need to use the string the variable-length argument list. That's why it is wrong.
  • The option b and c are all wrong because in the last parameter the variable-length argument list is used.

That's why the answer to this question is the option "d".

7 0
3 years ago
I just downloaded an update for my laptop. Now, it doesn't give me a notification when the battery is low, and it just shuts off
givi [52]
Have you tried resetting it on your own first ? Although, it could just be a bug from this update (being something you can't solve until the next one) But you can try resetting it, or going to settings and clicking on battey, maybe the update turned that off ? Sometimes they do that, too! I hope all is well. ((:
7 0
3 years ago
Juhfvehrfwhedfhwkefhkujhiuyuiyuiyiyh
maw [93]

Answer:

blah

blah

blah..⁉️

Explanation:

juhfvehrfwhedfhwkefhkujhiuyuiyuiyiyh

⁉️

8 0
3 years ago
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