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kakasveta [241]
3 years ago
12

Does increase in sample size increases degrees of freedom for t-tests.

Mathematics
1 answer:
Elena-2011 [213]3 years ago
3 0
Basically degrees of freedom are related to sample size (n-1). If the df increases, it also stands that the sample size is increasing; the graph of the t-distribution will have skinnier tails, pushing the critical value towards the mean.
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Tommy is baking a cake. He knows that he needs 2/3 cups of flour to make 4 cakes. How many cups of flour will Tommy need to make
mash [69]
1. 1/3 cups..... ok vthen have a good day
4 0
3 years ago
I Just want to know the difference in between graphing in two different ways...
aivan3 [116]

Answer:

It's simple.

Step-by-step explanation:

Inequalities that use < or > symbols are plotted with a dashed line to show that the line is not included in the region. Inequalities that use ≤ or ≥ symbols are plotted with a solid line to show that the line is included in the region.

5 0
3 years ago
The surface area of a cube is 400 millimeters what is the surface area of a similar cube that is larger by a scale factor of 3
yuradex [85]
Larger by 3 means that the legnths of the sides are larger by 3 times
so we have a cube that has area of 400
surface area=legnth times width times 6 since it is a cube and legnth=width
so
SA=w^2 times 6

6w^2=400
divide by 6
w^2=200/3
square root both sides
w=√(200/3)
so w is 3 times larger
(3w)^2 times 6 is new area

w=√(200/3)
(3√(200/3))^2 times 6=9(200/3) times 6=600 times 6=3600

answer is 3600 ml^2
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20lnx%20%7D%20" id="TexFormula1" title=" \sqrt[4]{ lnx } " alt=" \sqrt[4]
Kamila [148]

Use the power rule for differentiation:

\dfrac{\text{d}}{\text{d}x} (f(x))^k = k(f(x))^{k-1}f'(x)

You can use this formula if you remember that a root is just a rational exponential:

\sqrt[4]\ln(x) = (\ln(x))^{\frac{1}{4}}

So, remembering that the derivative of the logarithm is 1/x, you have

\dfrac{\text{d}}{\text{d}x} (\ln(x))^{\frac{1}{4}} = \frac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x}

Which you can rewrite as

\dfrac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x} =\dfrac{1}{4}(\ln(x))^{\frac{-3}{4}}\dfrac{1}{x} =\dfrac{1}{4}\dfrac{1}{\sqrt[4]{\ln(x))^3}}\dfrac{1}{x} = \dfrac{1}{4x\sqrt[4]{\ln(x))^3}}

3 0
3 years ago
To divide 1.89 ÷ 0.9, we need to change it. Choose the correct problem below to show what the “new” look would be.
Arlecino [84]

Answer:

D. 18.9 ÷ 9

Step-by-step explanation:

we need to divide

1.89 ÷ 0.9 but write it in different form

so ,we need to eliminate decimal from 0.9

as 0.9*10 = 9

thus,we multiply both  1.89 and  0.9 with 10, then we will have

(1.89*10) ÷ (0.9*10)

=> 18.9 ÷ 9

Thus, based on above calculation new look would be D. 18.9 ÷ 9

8 0
3 years ago
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