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kakasveta [241]
2 years ago
12

Does increase in sample size increases degrees of freedom for t-tests.

Mathematics
1 answer:
Elena-2011 [213]2 years ago
3 0
Basically degrees of freedom are related to sample size (n-1). If the df increases, it also stands that the sample size is increasing; the graph of the t-distribution will have skinnier tails, pushing the critical value towards the mean.
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What is the degree of the polynomial?<br><br> 4x3+3x2−9x+7
PolarNik [594]

Answer:

3

Step-by-step explanation:

The highest degree amount or exponet amount is the power of a equation.

3 is the highest exponet so it is 3.

7 0
2 years ago
part of the river she observed fell 1.68 millimeters per year for 1.5 years. Use the distributive property to calculate the exac
Alecsey [184]
1.68 mm per year for 1.5 years could be rewritten as 
(2.00-0.32) mm per year for 1.5 yrs.

Multiply:  (1.5 yrs)(2.00-0.32)(mm/yr) = 3 mm + 0.48 mm = 3.48 mm

This approach makes use of the distributive property of multiplication.
8 0
3 years ago
What is the median of this set of data?<br> 1, 2, 5, 6,9
Aleksandr-060686 [28]

Answer:

5

Step-by-step explanation:

median = (n+1)/2 th item

n = 5

median = 3rd item = 5

3 0
3 years ago
2 1/3 + 3/7 divided by 2 1/3 x 1 3/7​
oee [108]

Answer: \frac{29}{35}

Step-by-step explanation:

1. Make sure all your denominators are the same, you can do this by multiplying them all by 3 or 7, 2 and 1/3 would become 2 7/21, 3/7 would become 9/21, 2 and 1/3, would become 2 and 7/21, and so on and so forth, leaving us with

2\frac{7}{21}+\frac{9}{21} / 2\frac{7}{21} * 1\frac{9}{21}

2. Now, I would go and solve each side of the equation because we divide them, we can add 2\frac{7}{21} and \frac{9}{21}  together to get  2\frac{16}{21}, because 7 + 9 = 16

2\frac{16}{21} / 2\frac{7}{21} * 1\frac{9}{21}

3. We can do the same thing to the other side, by multiplying the two of them. I'm going to convert both of them to just fractions, 2\frac{7}{21} becomes \frac{49}{21} and 1\frac{9}{21} becomes \frac{30}{21}

\frac{49}{21} *  \frac{30}{21}

Now we can reduce them, and for our first fraction divide the top and bottom by 7, giving us  \frac{7}{3} and the second one by 3, which gives us  \frac{10}{7}

\frac{7}{3} * \frac{10}{7} now we cross divide, where we replace the 7's with ones because they're right across from each other to get  \frac{1}{3} and  \frac{10}{1}, or just 10.

\frac{1}{3} * 10 =  \frac{10}{3}

4. So now we can do a similar thing with the first half of our equation and convert it into a fraction and not a mixed number.

\frac{58}{21} / \frac{10}{3}

Now we multiply divide them, and the easiest way I learned how to do this was by keep the first fraction in its place, and flipping the denominator and numerator of the second, and multiplying them.

so   \frac{58}{21} * \frac{3}{10} which if we multiply both sides, you get \frac{174}{210}

I'll save you some times and simplify it for you, the greatest common factor is 6 so we divide the top and bottom by 6 to get

\frac{29}{35}

4 0
2 years ago
10 Points to the person who can help me. (What is the domain and range of the relation shown in the table?)
Firdavs [7]
Where is the table?.............?
4 0
3 years ago
Read 2 more answers
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