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Aleks04 [339]
3 years ago
8

I don't know how to solve this 2/4 + 3/8=?​

Mathematics
2 answers:
algol [13]3 years ago
6 0

Answer:

7/8

Step-by-step explanation:

look it up

your wel3

stellarik [79]3 years ago
5 0

Answer: \frac{7}{8} or 0.875 in decimal form.

Step-by-step explanation:

Okay, so to solve this, the easiest method is to find a common denominator. While we could try using trial and error or if you know your tables really well, I don't so we will just multiply the denominators which is 8 and 4. We then multiply 8 and 4 which is 32.

To convert the fractions we have, we multiply both the numerator and denominator of each, by the multiple that multiplies the denominator to 32.

\frac{2}{4} multiply both 4 and 2 by 8. Now we have \frac{16}{32}.

Same thing with the second number. We have \frac{3}{8}. We multiply both the numerator and the denominator by 4. 3*4 is 12, 8*4 is 32.

Now we have \frac{12}{32}.

Now that both fractions have common denominators, we can add the numerators. \frac{16}{32} +\frac{12}{32} = \frac{28}{32}

Now we have the answer, \frac{28}{32}, but is that it?

No. Now to find the final two answers, we simply \frac{28}{32}.

To simplify, we find the Greatest Common Factor of 28 and 32, which in this case happens to be 4. This is the highest number that either of those can be divided by to provide a normal whole number

After solving \frac{28/4}{32/4} =\frac{7}{8}

That is our final answer. \frac{7}{8}.

If necessary, you can convert it to decimal form through simple division and end up with 0.875.

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Which real-world situation can be represented by the expression 12n – 5?
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Step-by-step explanation:

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Step-by-step explanation:

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A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21
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Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{340119}{10} = 34011.9

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

S.D = \sqrt{\frac{2711418821}{9}} = 17357.09

Confidence interval:

\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)

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3 years ago
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