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Aleks04 [339]
2 years ago
8

I don't know how to solve this 2/4 + 3/8=?​

Mathematics
2 answers:
algol [13]2 years ago
6 0

Answer:

7/8

Step-by-step explanation:

look it up

your wel3

stellarik [79]2 years ago
5 0

Answer: \frac{7}{8} or 0.875 in decimal form.

Step-by-step explanation:

Okay, so to solve this, the easiest method is to find a common denominator. While we could try using trial and error or if you know your tables really well, I don't so we will just multiply the denominators which is 8 and 4. We then multiply 8 and 4 which is 32.

To convert the fractions we have, we multiply both the numerator and denominator of each, by the multiple that multiplies the denominator to 32.

\frac{2}{4} multiply both 4 and 2 by 8. Now we have \frac{16}{32}.

Same thing with the second number. We have \frac{3}{8}. We multiply both the numerator and the denominator by 4. 3*4 is 12, 8*4 is 32.

Now we have \frac{12}{32}.

Now that both fractions have common denominators, we can add the numerators. \frac{16}{32} +\frac{12}{32} = \frac{28}{32}

Now we have the answer, \frac{28}{32}, but is that it?

No. Now to find the final two answers, we simply \frac{28}{32}.

To simplify, we find the Greatest Common Factor of 28 and 32, which in this case happens to be 4. This is the highest number that either of those can be divided by to provide a normal whole number

After solving \frac{28/4}{32/4} =\frac{7}{8}

That is our final answer. \frac{7}{8}.

If necessary, you can convert it to decimal form through simple division and end up with 0.875.

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Yes, 2 ≤ x ≤ 5 is an inequality.

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If a point is the midpoint of a segment, then it divides the segment into two congruent segments. R is the midpoint of QS. Concl
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All given information leads to conclusion described on statement. (QR = RS)

Step-by-step explanation:

The strategy of problem consist in make a mathematical demonstration from given information. There are two assumptions: i) R is a point of segment QS and ii) R is the midpoint of QS. We proceed to perform the demonstration:

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