Answer:
Final answer is 
Step-by-step explanation:
We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).
So first we need to find the slope of given line.
rewirite x=6y-5 in y=mx+b form
x+5=6y
Compare given equation with y=mx+b
we get: m=1/6
We know that parallel equations has equal slope.
Then slope of required line m=1/6
Now plug the given point (5,-3) and slope m=1/6 into point slope formula:
Now we need to rewrite that equation in standard form. Ax+By=C.
6y=x-23
x-23=6y
x-6y=23
Hence final answer is
Answer:
Step-by-step explanation:
Hi there!
Linear equations are typically organized in slope-intercept form: 
where m is the slope (also called the gradient) and b is the y-intercept (the value of y when x is 0)
<u>1) Plug the gradient into the equation (b)</u>
We're given that the gradient of the line is 4. Plug this into as m:
<u>2) Determine the y-intercept (b)</u>
Plug in the given point (1,10) as (x,y) and solve for b
Subtract 4 from both sides to isolate b
Therefore, the y-intercept of the line is 6. Plug this back into as b:
I hope this helps!
Answer:
Slope: 1/4
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
2< 9(5) + 4
2 < 45 + 4
2 < 49
