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Natali5045456 [20]
3 years ago
11

What is the equation of the midline for the function f(x)?

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
4 0

9514 1404 393

Answer:

  f(x) = 3

Step-by-step explanation:

Replace sin(x) with 0 and you will have it.

  f(x) = 12·0 +3

  f(x) = 3

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Gold fish or cheez its​
babymother [125]

Answer: gold fish

Step-by-step explanation:

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3 years ago
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A city spent about 1/4 of its budget on buildings and maintenance, which was about 1/8 of the total budget less than it spent on
Yuliya22 [10]

Answer:

1/8 of the budget was left for other expenses.

Step-by-step explanation:

1/4 of the budget - buildings and maintenance.

Administrative personnel :  1/4 + 1/8 = 2/8 + 1/8 = 3/8 of the budget.

Therefore:

3/8 of the budget - administrative personnel.

Public safety :  3/8 - 1/8 = 2/8 = 1/4 of the budget.

For other expenses :

1 - ( 1/4 + 3/8 + 1/4 ) = 1 - ( 2/8 + 3/8 + 2/8 ) 1 - 7/8 = 1/8

Finally, 1/8 of the total budget was for the other expenses.

6 0
3 years ago
An equo equila Teral Traingle has
Murljashka [212]

Answer:

Step-by-step explanation:

Given parameters:

Dimensions of the equilateral triangle = 6.2cm

Unknown:

Perimeter = ?

Solution:

The perimeter of the triangle is the sum of all its sides;

  Perimeter = 3(L) for an equilateral triangle;

 Perimeter  = 3(6.2) = 18.6cm

to the nearest mm = 19.0cm

6 0
4 years ago
A cylinder has a base diameter of 14m and a height of 10m. What is its volume in cubic m, to the nearest tenths place?
VARVARA [1.3K]

Answer:

1539 cubic meters

Step-by-step explanation:

Hello, I can help you with this

to solve need  we will need these two equations

Step one

Remember

area of a circle

Area=\pi *\frac{diameter^{2} }{4}\\

Also, the volume of the cylinder

Volume= area of the circle * height

Volume=\pi *\frac{diameter^{2} }{4} *height\\

Step 2

put the values into the equation

Let

diameter= 14 m

height = 10 m

Volume=\pi *\frac{diameter^{2} }{4} *height\\\\Volume=\pi *\frac{(14\ m)^{2} }{4} *10\ m \\\\Volume=\pi *49\ m^{2} *10\ m\\Volume=1539.38\ cubic\ meters

I hope it helps,have a great day.

3 0
3 years ago
lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.
zaharov [31]

Answer with Step-by-step explanation:

Given

f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1

6 0
3 years ago
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