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Taya2010 [7]
3 years ago
14

What is the difference between 1 and o.1978​

Mathematics
1 answer:
Vlad1618 [11]3 years ago
6 0

Answer:

0,8022

Step-by-step explanation:

guess it helped

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In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the
oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

\mu = 503, \sigma = \sqrt{9604} = 98

So

Z = \frac{X - \mu}{\sigma}

1.476 = \frac{X - 503}{98}

X - 503 = 1.476*98

X = 648

Abby's score

She scored 648.

\mu = 521 \sigma = \sqrt{10201} = 101

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{648 - 521}{101}

Z = 1.26

Z = 1.26 has a pvalue of 0.8962.

The percentle for Abby's score was the 89.62nd percentile.

3 0
3 years ago
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