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dimaraw [331]
3 years ago
8

Which of these completes the sentence? People interpret information ___________. Choose one.

Computers and Technology
2 answers:
evablogger [386]3 years ago
5 0

Explanation:

mannejaondpsbma0jdjdhdj

alexandr402 [8]3 years ago
3 0
Hhhhgtfw sn jbhhjmbfbnkgy
You might be interested in
Need help asap please
Bumek [7]

Answer:

options is right

Explanation:

3 0
2 years ago
Write a program to find all integer solutions to the equation 4x + 3y -9z = 5 for values of x, y, and z between 0 to 100.
rjkz [21]

Answer:

Following are the code to the given question:

#include <iostream>//header file

using namespace std;

int main()//main method

{

  int c= 0;//defining integer variable to count number of solutions

  int x,y,z;//defining integer variable which is used in the loop

  for (x = 0; x <= 100; x++)//defining for loop to x value

     for (y = 0; y <= 100; y++)//defining for loop to y value

        for (z = 0; z <= 100; z++)//defining for loop to z value

           if (4 * x + 3 * y - 9 * z == 5)//use if to check given condition

           {

              c++;//increment count value

              cout << "(" << x << "," << y << "," << z << ")";//print solutions  

              cout << (c % 11? " " : "\n");//use for add file solution in a row

           }

  cout << "\n\nThere are " << c << " solution(s)\n";//print solution couts

  return 0;

}

Output:

Please find the attached file.

Explanation:

In the above-given code four integer variable "x,y,z, and c" is declared, in which "x,y, and z" is used in the for loop with the if conditional statement that checks the given condition and prints the solution and the "c" variable is used to counts the number of solution, and at the last, it uses the print method to print its values.  

8 0
3 years ago
Assume you're using a three-button mouse. To access shortcut menus, you would
irina1246 [14]
If you are using the three-button mouse, in order to access the shortcut menus, you would right click the mouse. 
If you right click your mouse, it will show shortcut menus that can be easily accessed.
5 0
3 years ago
Flash drive / USB is ___________ device. A)Input B)Output C)Internal D)None of these
svetlana [45]

Explanation:

USB is a output devices

7 0
1 year ago
Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth
telo118 [61]
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}


So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.


4 0
3 years ago
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