All categories

3 years ago

PLEASE HELP A FRIEND IN NEED

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

7 0

When multiplying you add the powers so it’s -4+-5 but it gets confusing as 2 negatives make a positive. So it’s essentially 4+5 which is 9

You might be interested in

40 is what percent of 160?

mash [69]

Answer:

Step-by-step explanation:

percentage calculator 40 is what percent of 160=25;)

4 0

3 years ago

Read 2 more answers

Help me pleaseeeeeee

morpeh [17]

Answer:

Step-by-step explanation:

u move the decimal place left 2 spaces and u would get 0.024

3 0

3 years ago

The cost of 5 hats and 1 scarf is $47. The cost of 2 hats and 2 scarves is $40. How much does one hat cost?

stepan [7]

Answer:

6.75

Step-by-step explanation:

h=hat, s=scarf

5h + 1s = $47 (equation 1)

2h + 2s = $40 (equation 2)

multiply equation 1 by 2 , we get: 10h + 2s = $94 (equation 3)

equation 3 minus equation 2, we get:

8h = $54 ⇒ h = $6.75 ⇔ 1 hat cost $6.75

substitute h = $6.75 into equation 2 to find s,

2($6.75) + 2s = $40

$13.5 + 2s = $40

2s = $26.5

s = $13.25 ⇔ 1 scarf cost $13.25

6 0

3 years ago

A machine that produces a major part for an airplane engine is monitored closely. In the past, 10% of the parts produced would b

nata0808 [166]

Answer:

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$p = 0.1$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is

We need a sample size of at least n, in which n is found M = 0.04.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.1*0.9}{n}}$

$0.04\sqrt{n} = 0.588$

$\sqrt{n} = \frac{0.588}{0.04}$

$\sqrt{n} = 14.7$

$(\sqrt{n})^{2} = (14.7)^{2}$

$n = 216$

With a .95 probability, the sample size that needs to be taken if the desired margin of error is .04 or less is of at least 216.

7 0

3 years ago

A 7-foot tall stop sign creates a shadow that is 2 feet long. At the same time, a utility pole creates a shadow that is 10.4 fee

barxatty [35]

38.5 ft tall

is the answer to your question

plz rate 5 stars

8 0

3 years ago