Answer:
The graph of y2+3x=0 is symmetric with respect to the x-axis
Step-by-step explanation:
To establish symmetry with respect to the x-axis we simply substitute -y in place of y in the original equation. If the resulting equation is identical to the original one then the function is said to be symmetric with respect to the x-axis.
In this case we have;
Which is identical to the original equation
This is a quadratic so if you want to find the solutions, use the quadratic formula. Google quadratic formula and videos on it and how to use it will pop up.
The slope will be -1/2. If you put it into slope intercept form of y=mx+b, mx will always be the slope.
Answer: C
since the line isn't straight, the slope/function is decreasing but not at a constant rate
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].
The width of each rect. is 1/2.
The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.
The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:
{1.875, 2.5, 2.875}
Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?
