5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/
Answer:Sara hina and Arslan Have RS79.4,RS 72.4 and RS238.2 respectively.
Step-by-step explanation:
Step 1
Let the amount that hina has be x
the amount that sara has be represented as 7+x
and the amount that Arslan have be represented as 3(7+x)
such that the total amount in their wallet which is 390 can be expressed as
x+7+x + 3(7+x)=390
Step 2
Solving
x+7+x +21+3x=390
5x+28=390
5x==390-28
x=362/5=72.4
Hina has RS 72.4
Sara =7+x==72.4+77= RS 79.4
Arslan =3(7+x)=3 x 79.4=RS 238.2
Answer:
50 in total, 45 were eaten
Step-by-step explanation:
If there's only 10% left and 10% is 5 cookies, then that means for every 10% is 5 cookies so 90 x 5 = 45
N= 8
b/c if u do it backwards 5*1.6=8- you get 8
and to check 8/1.6=5
so n= 5
hope this helps
