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Drupady [299]
2 years ago
6

Does anybody know how to solve this problem?

Mathematics
1 answer:
Advocard [28]2 years ago
3 0

Answer:BC=68

DE=36

CE=34

Step-by-step explanation:

Since  D, E and F are the midpoints, they follow the midpoint theorm which states that "The line segment in a triangle joining the midpoint of two sides of the triangle is said to be parallel to its third side and is also half of the length of the third side." As for others, it's just the calculation.

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D) increase the thrust force and increase the mass of the rocket.
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Does anyone know what's asked for flvs pre Calc module 4 dba
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7 0
3 years ago
I need the domain range and function. With an explanation
erastovalidia [21]
<h3>Answers:</h3>

Problem 1

  • Domain = -3 < x \le 3, interval notation (-3, 3]
  • Range = -3 \le y < 3, interval notation [-3, 3)
  • Is it a function? Yes

Problem 2

  • Domain = x \ge -2, interval notation [-2, \infty)
  • Range = All real numbers, interval notation (-\infty, \infty)
  • Is it a function? No

Problem 3

  • Domain = -4 \le x < 3, interval notation [-4, 3)
  • Range = -4 < y \le 3, interval notation (-4, 3]
  • Is it a function? Yes

Problem 4

  • Domain = All real numbers, interval notation (-\infty, \infty)
  • Range = y \le 4, interval notation (-\infty, 4]
  • Is it a function? Yes

==================================================

Explanations:

  1. The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore -3 < x \le 3 which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
  2. The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is x \ge -2 which in interval notation is [-2, \infty). The range is (-\infty, \infty) to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
  3. This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
  4. This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is y \le 4 which is the same as saying (-\infty, 4] in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

7 0
3 years ago
How many quart are 8/1/4 gallons
Westkost [7]

Given:

Consider the given gallons are 8\dfrac{1}{4} gallons.

To find:

The number of quarts in 8\dfrac{1}{4} gallons.

Solution:

We know that,

1 gallons = 4 quarts

Using this conversion, we get

8\dfrac{1}{4}\text{ gallons}=4\times 8\dfrac{1}{4}\text{ quarts}

8\dfrac{1}{4}\text{ gallons}=4\times \dfrac{32+1}{4}\text{ quarts}

8\dfrac{1}{4}\text{ gallons}=4\times \dfrac{33}{4}\text{ quarts}

8\dfrac{1}{4}\text{ gallons}=33\text{ quarts}

Therefore, there are 33 quarts in 8\dfrac{1}{4} gallons.

6 0
2 years ago
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Fudgin [204]

Answer: 1. HA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.

2. HL can be a reason to show given triangles are congruent as the triangles are right triangle with equal legs and hypotenuse.

3. SAS can be a reason to show given triangles are congruent as there are  two congruent sides in both triangles and included angles ∠A=∠D=90° [right angle].

4. LA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.

5. AAS  cannot be a reason to show given triangles are congruent as it is not given that they have two angles common in both the triangles.

6.SSS can be a reason to show given triangles are congruent as it is shown that all the sides of one triangle is congruent to the other.

HOPE THIS HELPS

6 0
2 years ago
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