80 hr total
the assistants is not info
25 hr X $22 per = $500
15 hr X $10 = $150
$500 + $150 = $650
now for hr you have 80, you worked 25 + 15 = 40, 80 - 40 = 40
your answer is 40 --------------------------------------|^|
your welcome
Hey there!!
Given equation :
... x² + x - 6 = 0
... x² -2x + 3x - 6 = 0
... x ( x - 2 ) + 3 ( x - 2 ) = 0
... ( x + 3 ) ( x - 2 ) = 0
Option ( b )
Hope it helps!
Step-by-step explanation:
t1= 2-3-6=-7
t2= 8-6-6=-4
t3=18-9-6=3
Answer:
170
Step-by-step explanation:
The given relations can be used to write and solve an equation for the number of stickers Peter has.
<h3>Setup</h3>
Let p represent the number of stickers Peter has. That is twice as many as Joe, so Joe has (p/2) stickers. Joe has 40 more stickers than Emily, so the number of stickers Emily has is (p/2 -40).
The total number of stickers is 300:
p +p/2 +(p/2 -40) = 300
<h3>Solution</h3>
2p = 340 . . . . . . . . . . . . . . add 40, collect terms
p = 170 . . . . . . . . . . . divide by 2
Peter has 170 stickers.
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<em>Additional comment</em>
Joe has 170/2 = 85 stickers. Emily has 85-40 = 45 stickers.
We could write three equations in three unknowns. Solving those using substitution would result in substantially the same equation that we have above. Or, such a system of equations could be solved using a calculator's matrix functions, as in the attachment.
p +j +e = 300
p -2j +0e = 0
0p +j -e = 40
Answer:
P-value is lesser in the case when n = 500.
Step-by-step explanation:
The formula for z-test statistic can be written as

here, μ = mean
σ= standard deviation, n= sample size, x= variable.
From the relation we can clearly observe that n is directly proportional to test statistic. Thus, as the value of n increases the corresponding test statistic value also increases.
We can also observe that as the test statistic's numerical value increases it is more likely to go into rejection region or in other words its P-value decreases.
Now, for first case when our n is 50 we will have a relatively low chance of accurately representing the population compared to the case when n= 500. Therefore, the P-value will be lesser in the case when n = 500.