Answer:
1/5
Step-by-step explanation:
Answer:
Srue what's your question
Step-by-step explanation:
Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
<span>–4(x + 3) ≤ –2 – 2x
>>.....-4x -12 </span>≤ -2 -2x
>> -12 +2 ≤ +2x
>> - 10 ≤ 2x
>> -5 ≤ x............>> x >= -5
This answer is not represented in the pictures you attached
The line starts in x = -5 and goes up to infinity
X+3y=7
x-3y=1
add them together
x+3y=7
<u>x-3y=1 +
</u>2x+0y=8
2x=8
divide 2
x=4
subsitute
x+3y=7
4+3y=7
subtract 4
3y=3
divid 3
y=1
x=4
y=1
answer is A
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