All categories

3 years ago

Find the equation of the linear relationship.

Mathematics

1 answer:

rosijanka [135]3 years ago

3 0

Answer:

y = -3x + 150

Step-by-step explanation:

2 points on the graph:

(30, 60) and (40, 30)

Slope:

m=(y2-y1)/(x2-x1)

m=(30 - 60)/(40 - 30)

m= (-30)/10

m= -3

Slope-intercept:

y - y1 = m(x - x1)

y - 60 = -3(x - 30)

y - 60 = -3x + 90

y = -3x + 150

You might be interested in

If a car is moving at the speed of 60 miles per hour how many miles would a car travel i 120 minutes

sertanlavr [38]

Answer:

120 miles

Step-by-step explanation:

120minutes= 2hour

2×60÷1=120 (miles)

8 0

3 years ago

NO LINKS. 20 POINTSSS

vladimir2022 [97]

Answer:

probably d sorry i couldnt alot

4 0

3 years ago

The measure angle A is (2x+3), B (4x+2), C (2x-1). What are the measures of the angles?

Rudik [331]

Answer:

<A= 47, <B= 90, <C= 43

Step-by-step explanation:

2x +3 + 4x + 2 + 2x-1 = 180

8x + 4= 180

8x = 176

x =22

2x+3= 44+3= 47

4x+2 = 88+2 = 90

2x-1= 44-1 = 43

8 0

3 years ago

Select all the expressions that are equivalent to the polynomial below.

katrin2010 [14]

The answers are: D and C and A and E
because:

B 3(x - 5) - 2(6x2 + 9x + 5)=−12x^2−15x−25

F (4x2 - 13x - 7) - (16x2 + 9x - 5)=−12x2−22x−2

E (-15x2 + 9x - 10) + (3x2 - 10x - 5)=−12x^2−x−15

4 0

3 years ago

Read 2 more answers

The logarithmic expression ln(√e/y^3) can be rewritten as

kvv77 [185]

Answer:

$\dfrac{1 - 6 \ln y}{2}$

Step-by-step explanation:

$\ln \dfrac{\sqrt{e}}{y^3} =$

$= \ln \dfrac{e^\frac{1}{2}}{y^3}$

$= \ln e^\frac{1}{2} - \ln y^3$

$= \dfrac{1}{2} \ln e - 3 \ln y$

$= \dfrac{1}{2} - 3 \ln y$

$= \dfrac{1 - 6 \ln y}{2}$

6 0

3 years ago