The exponential growth is: 
And its graph is the first one.
The exponential decay is: 
And its graph is the second one.
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How to identify the exponential equations?</h3>
The general exponential equation is of the form:

Where A is the initial value and b is the base.
- If b > 1, then we have an exponential growth.
- if 1 > b > 0, then we have an exponential decay.
Here the two functions are:


As you can see, the base for the first one is smaller than 1, then it is an exponential decay (and it has a decreasing graph, so the graph of this one is the second graph).
For the second function, we have the base b = 1.25, which is larger than 1, so it is an exponential growth, and its graph is an increasing graph, which is the first one.
If you want to learn more about exponential functions:
brainly.com/question/11464095
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Answer:
- Overall GPA=2.81
- It is not possible to get his GPA to 3.0 for graduation.
Step-by-step explanation:
The Student already has a GPA of 2.68 after 108 credit hours.
If he is taking 12 credit hours in his last semester and gets a perfect 4.0 GPA
Total Credits Earned Before = 2.68 X 108=2894.4
Projected Credit to be earned = 12 X 4= 48 Credits
Total credit Hour= 108+12=120 Hours
His Cumulative GPA = Total credits earned ÷ Total Credit Hour

Since 2.81 is less than 3.00, it is not possible to get his GPA to 3.0 for graduation.
Evaluate A² for A = -3.
(-3)² = (-3) * (-3) = 9
Your answer is 9.
If the question is, however, evaluate A2, which is 2A, for A = -3, then the answer is:
2A = 2(-3) = -6.
Answer:
It would take him 450 minutes to burn off the calories by sleeping
Step-by-step explanation:
Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
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f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
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g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).