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3 years ago

I need help please. Thank you!

Mathematics

1 answer:

rjkz [21]3 years ago

7 0

the correct answer is C 1/4

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8-37 better than or equal to 29

Zina [86]

The statement that 8-37 greater than or equal to 29 is false and the correct statement is 8 - 27 is less than 29

<h3>What is an inequality?</h3>

An inequality can be defined as a relation which makes an unequal comparison between two numbers or mathematical expressions.

It is used most often to compare two numbers on the number line by their size

The information given be represented as;

$8 - 37\geq 29$

Now, let's find the difference from the left side

We have;

$- 29\geq 29$

From this, we can see that the statement is wrong as - 29 is neither greater than or equal to 29

The correct statement should be; 8 - 27 is less than 29

Thus, the statement that 8-37 greater than or equal to 29 is false and the correct statement is 8 - 27 is less than 29

Learn more about inequalities here:

brainly.com/question/24372553

#SPJ1

5 0

2 years ago

Jenna's band is going to record a CD at a recording studio. They will pay $125 to use the studio for one day and $90 per hour fo

Strike441 [17]

Answer:

yes

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the sum of the fractions? Use the number line and equivalent fractions to help find the answer.

Alchen [17]

<h3>Answer: -3/4 (choice C)</h3>

==================================================

Explanation:

Think of a whole cake or pizza. Now slice it into 4 equal pieces. This represents 1 is the same as 4/4.

Adding on another quarter slice gets us 4/4+1/4 = 5/4

In other words, the mixed number 1 & 1/4 is the same as the improper fraction 5/4.

So 1 & 1/4 = 5/4

This then means -1 & 1/4 = -5/4 because we multiply both sides by -1.

Now we'll add on 1/2, which is the same as 2/4, like so

(-1 & 1/4) + 1/2

-(1 & 1/4) + 2/4

-(1 + 1/4) + 2/4

-1 - 1/4 + 2/4

-1 + (-1/4 + 2/4)

-1 + 1/4

-4/4 + 1/4

-3/4

which points us to choice C as our final answer

Notice how if we started at -5/4, and moved to the right 2 tickmarks, we arrive at -3/4. Each tickmark represents 1/4 of a unit, so two of them is 2/4 = 1/2.

Side note: -3/4 converts to the decimal -0.75

6 0

3 years ago

Use the given information to find (a) sin(s+t), (b) tan(s+t), and (c) the quadrant of s+t. cos s = - 12/13 and sin t = 4/5, s an

Anton [14]

Answer:

Part a) $sin(s + t) =-\frac{63}{65}$

Part b) $tan(s + t) = -\frac{63}{16}$

Part c) (s+t) lie on Quadrant IV

Step-by-step explanation:

[Part a) Find sin(s+t)

we know that

$sin(s + t) = sin(s) cos(t) + sin(t)cos(s)$

step 1

Find sin(s)

$sin^{2}(s)+cos^{2}(s)=1$

we have

$cos(s)=-\frac{12}{13}$

substitute

$sin^{2}(s)+(-\frac{12}{13})^{2}=1$

$sin^{2}(s)+(\frac{144}{169})=1$

$sin^{2}(s)=1-(\frac{144}{169})$

$sin^{2}(s)=(\frac{25}{169})$

$sin(s)=\frac{5}{13}$ ---> is positive because s lie on II Quadrant

step 2

Find cos(t)

$sin^{2}(t)+cos^{2}(t)=1$

we have

$sin(t)=\frac{4}{5}$

substitute

$(\frac{4}{5})^{2}+cos^{2}(t)=1$

$(\frac{16}{25})+cos^{2}(t)=1$

$cos^{2}(t)=1-(\frac{16}{25})$

$cos^{2}(t)=\frac{9}{25}$

$cos(t)=-\frac{3}{5}$ is negative because t lie on II Quadrant

step 3

Find sin(s+t)

$sin(s + t) = sin(s) cos(t) + sin(t)cos(s)$

we have

$sin(s)=\frac{5}{13}$

$cos(t)=-\frac{3}{5}$

$sin(t)=\frac{4}{5}$

$cos(s)=-\frac{12}{13}$

substitute the values

$sin(s + t) = (\frac{5}{13})(-\frac{3}{5}) + (\frac{4}{5})(-\frac{12}{13})$

$sin(s + t) = -(\frac{15}{65}) -(\frac{48}{65})$

$sin(s + t) =-\frac{63}{65}$

Part b) Find tan(s+t)

we know that

tex]tan(s + t) = (tan(s) + tan(t))/(1 - tan(s)tan(t))[/tex]

we have

$sin(s)=\frac{5}{13}$

$cos(t)=-\frac{3}{5}$

$sin(t)=\frac{4}{5}$

$cos(s)=-\frac{12}{13}$

step 1

Find tan(s)

$tan(s)=sin(s)/cos(s)$

substitute

$tan(s)=(\frac{5}{13})/(-\frac{12}{13})=-\frac{5}{12}$

step 2

Find tan(t)

$tan(t)=sin(t)/cos(t)$

substitute

$tan(t)=(\frac{4}{5})/(-\frac{3}{5})=-\frac{4}{3}$

step 3

Find tan(s+t)

$tan(s + t) = (tan(s) + tan(t))/(1 - tan(s)tan(t))$

substitute the values

$tan(s + t) = (-\frac{5}{12} -\frac{4}{3})/(1 - (-\frac{5}{12})(-\frac{4}{3}))$

$tan(s + t) = (-\frac{21}{12})/(1 - \frac{20}{36})$

$tan(s + t) = (-\frac{21}{12})/(\frac{16}{36})$

$tan(s + t) = -\frac{63}{16}$

Part c) Quadrant of s+t

we know that

$sin(s + t) =negative$ ----> (s+t) could be in III or IV quadrant

$tan(s + t) =negative$ ----> (s+t) could be in III or IV quadrant

Find the value of cos(s+t)

$cos(s+t) = cos(s) cos(t) -sin (s) sin(t)$

we have

$sin(s)=\frac{5}{13}$

$cos(t)=-\frac{3}{5}$

$sin(t)=\frac{4}{5}$

$cos(s)=-\frac{12}{13}$

substitute

$cos(s+t) = (-\frac{12}{13})(-\frac{3}{5})-(\frac{5}{13})(\frac{4}{5})$

$cos(s+t) = (\frac{36}{65})-(\frac{20}{65})$

$cos(s+t) =\frac{16}{65}$

we have that

$cos(s+t)=positive$ -----> (s+t) could be in I or IV quadrant

$sin(s + t) =negative$ ----> (s+t) could be in III or IV quadrant

$tan(s + t) =negative$ ----> (s+t) could be in III or IV quadrant

therefore

(s+t) lie on Quadrant IV

4 0

3 years ago

I need some help.I don't understand this question and i have tried to answer it mutiple times but i get it wrong.

miskamm [114]

Answer:

(5,-3)

Step-by-step explanation:

y+3 = 3x-15

y= -2x + 7

plulg y in

-2x+7+3 = 3x-15

combine like terms

-2x+10 = 3x-15

add 2x to both sides and add 15 to both

5x=25

x=5

y=-2(5) + 7

y= -10 + 7

y= -3

(5,-3)

6 0

2 years ago

I need help please. Thank you!​

I need help please. Thank you!