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Nikolay [14]
3 years ago
13

How many solutions y=x^2-10x+25

Mathematics
1 answer:
MrRissso [65]3 years ago
7 0
<h2>There are infinite solution of y.</h2>

Step-by-step explanation:

Given,

y = x^2 - 10x + 25

To find, the total number of solutions = ?

∴ y = x^2 - 10x + 25

⇒ y = x^2 - 2(x)(5) + 5^2

⇒ y = (x-5)^{2}

There are infinite solution of y.

Thus, there are infinite solution of y.

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2/3 cup of oatmeal is needed to make 10 granola bars. How many such granola bars can be made with 20 cups of oatmeal ?
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3 years ago
Latisha worked for six hours and 45 minutes how should she write that on her time card
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2 years ago
The perimeter of a square is equal to four times the length of a side. Write the direct v variation equation that represents the
sveticcg [70]

Answer: y=4x

Step-by-step explanation:

A direct variation equation has the form:

y=kx

Where <em>k</em> is a constant.

By definition, we know that the perimeter of the square is the sum of the lengths of its sides or, as all the sides are equal, you can multiply the lenght of any side by 4.

 Then, knowing that <em>y</em> is the dependent value and <em>x</em> the independent value and the constant <em>k=4, </em> you can write the following direct variation equation that represents the situation.

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4 0
3 years ago
How many solutions does the nonlinear system of equations graphed below have
klio [65]

Answer:

The nonlinear system of equations has 4 solutions ⇒ B

Step-by-step explanation:

The number of solutions of a system of equations equal to the number of points of intersection of the graphs of the equations of the system

Let us use this note to solve the question

From the given figure

∵ The nonlinear system of equations represented by two curves and a circle

∵ Each curve intersects the circle into two points

∴ The number of the points of intersection is 4

→ By using the note above

∵ The number of intersection points equal to the number of solutions

∴ The number of solutions is 4

∴ The nonlinear system of equations has 4 solutions

8 0
3 years ago
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