Answer:
A.
Step-by-step explanation:
Hope this helps and have a great day!!!!
Answer:
D) 1980 to 2000
Step-by-step explanation:
Finding the average rate of change in each interval to determine the greatest one.
Production per interval
1950-1960 =
= 10 million
1960-1970 =
= 20 million
1970-1980 =
= 30 million
1980-2000 =
million
Rate of change (1950-1960)= ![\frac{10}{11} \times 100= 90.90\%](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B11%7D%20%5Ctimes%20100%3D%2090.90%5C%25)
Rate of change (1960-1970) = ![\frac{20}{21} \times 100= 95.23\%](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B21%7D%20%5Ctimes%20100%3D%2095.23%5C%25)
Rate of change (1970-1980)= ![\frac{30}{41} \times 100= 73.17\%](https://tex.z-dn.net/?f=%5Cfrac%7B30%7D%7B41%7D%20%5Ctimes%20100%3D%2073.17%5C%25)
Rate of change (1980-2000)= ![\frac{90}{71} \times 100= 126.76\%](https://tex.z-dn.net/?f=%5Cfrac%7B90%7D%7B71%7D%20%5Ctimes%20100%3D%20126.76%5C%25)
∴ rate of change between 1980 to 2000 is 126.78%
Hello!
Angle A has the same one line mark as angle Z. This makes them congruent. The same with B and X, but with a two line mark. This means C is congruent to Y.
This means our answer is D.
I hope this helps!
Differentiating both sides of PV = C with respect to t gives us ...
... P'V +PV' = 0
Filling in the given numbers gives us ...
... (40 kPa/min)(900 cm³) + V'(150 kPa) = 0
Solving for V' gives ...
... V' = -(40 kPa/min)(900 cm³)/(150 kPa)
.. V' = -240 cm³/min
The volume is decreasing at the rate of 240 cm³/min.