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alexira [117]
3 years ago
10

Find the value of x.

Mathematics
2 answers:
Paul [167]3 years ago
8 0

You have to put a complete question in order for us to answer your question!

Sergio039 [100]3 years ago
3 0

Answer:

can you please show attachments?

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Which compound inequality has no solution? x ≤ –2 and 2x ≥ 6 x ≤ –1 and 5x ≤ 5 x ≤ –1 and 3x ≥ –3 x ≤ –2 and 4x ≤ –8 ITS NOT D
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Look at the figure shown below:
boyakko [2]

These are the steps, with their explanations and conclusions:


1) Draw two triangles: ΔRSP and ΔQSP.


2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).


3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.


4) The segment SP is common to both ΔRSP and Δ QSP.


5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.


Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q


6 0
3 years ago
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Round 23,421 to the nearest thousand and ten thousand
Ronch [10]
To the nearest thousand is 23,000 and the nearest ten thousand is 20,000
8 0
3 years ago
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3. (05.06 MC)
AveGali [126]

Answer:

Step-by-step explanation:

y > 3x + 10

y < -3x - 1

<h3> Part A:</h3>

You'd graph the given systems of linear inequalities the same way as you graph the linear equations.  

To graph y > 3x + 10, plot the y-intercept, (0, 10), then use the slope, m = 3 (rise 3, run 1), to plot other points on the graph.  Use a dashed line (because of the ">" symbol).  

Follow the same steps for the other linear inequality. Plot the y-intercept, (0, -1), then use the slope, m = -3 (down 3, run 1) to plot other points. Use a dashed line (because of the "<" symbol).  

Pick a test point on either side of the boundary line and plug it into the original problem.  This will help determine which side of the boundary line is the solution.  Plug in a test point that is not on the boundary line.

Use the point of origin, (0, 0) as the test point. Plug in these values into the given systems of linear inequalities to see whether it will provide a true statement.  

y > 3x + 10

0 > 3(0) + 10

0 > 0 + 10

0 > 10 (False statement).  

y < -3x - 1

0 < -3(0) - 1

0 < 0 - 1

0 < -1 (false statement).  

Since the point of origin provided a false statement to the given systems of linear inequalities, you must shade the half-plane region where it doesn't contain the test point.  

<h3>Part B: </h3>

You'll do the same process as what I've done for the test point. Plug in the values of (8, 10) into the given systems of linear inequalities. If it provides a false statement, then it means that it is not a solution to the system.  

y > 3x + 10

10 > 3(8) + 10

10 > 24 + 10

10 > 34 (False statement).  

y < -3x - 1  

10 < -3(8) - 1

10 < -24 - 1

10 < -25 (false statement).  

Therefore, (8, 10) is not a solution to the system.    

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3 years ago
Translate the word phrase 2 less than 4 times a number into an algebra expression
Gala2k [10]

Answer:

D

Step-by-step explanation:

Extending answer to be able to send.

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3 years ago
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