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pochemuha
3 years ago
15

Please help with both problems thank you!

Mathematics
2 answers:
Serggg [28]3 years ago
5 0

Answer:

x > 3

Step-by-step explanation:

Elan Coil [88]3 years ago
5 0

Your answer would be.

1. x

2. r \geq 21

-Yaoii

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PLEASE ANSWERRRRRRRRR
chubhunter [2.5K]

Answer:

0

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Need help on all these questions!!
Yuki888 [10]

Okay, so YZ = 3 cm.  You have XM correct. And YM = 0.5.

Now, you have the midpoint M at the correct spot.

Use Pythagorean's theorem o find the length of AB.  a² + b² = c²   a=6,  b=8.

6² = 36   8² = 64    36 + 64 = 100      AB = 10!

If AB = 10   then AM = 5    MB also = 5

If B is the midpoint of AC,  C would be 12 rows down from A, and 16 columns to the right. The last spot where the line intersects.

There are your answers!

5 0
3 years ago
Find the perimeter of the figure when l = 15 m, w = 9 m, x = 3 m, and y = 6 m
Andru [333]

Answer:

54

Step-by-step explanation:15+15+9+9+3+3=54

8 0
3 years ago
Can some one answer this plz ill give !100 POINTS!
Lorico [155]
Hello!

First of all let's find the perimeter (circumference) of the semi circles. We can combine them to make one circle with a diameter of 4 (as we can see the side length of one semi circle is 4 cm. We now plug it into the circumference equation (\pi=3.14).

4(3.14)=12.56

Now we add up the side lengths of the rectangle.

4+6+4+6=20

Now we add up the length of our circle and rectangle.

20+12.56=32.56

Therefore our answer is 32.56 cm.
----------------------------------------------------------

Now to find the area! If we combine the two semicircles, we get a circle with a diameter of four. This means that is has a radius of two. We use the equation below to find the area of the two circles.

A=\pir²

First we will square our radius.

2(2)=4

Now we multiply by pi.

4(3.14)=12.56

Now we need to find the area of the rectangle.

6(4)=24

Now we add.

24+12.56=36.56.

 
I hope this helps!

8 0
4 years ago
Read 2 more answers
Can someone help please (highlighted in blue)
Annette [7]

\implies {\blue {\boxed {\boxed {\purple {\sf {B)\:10}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

4 + 3 \: ( \: 10 -  {2}^{3}  \: )

➺\: 4 + 3 \: ( \: 10 - 2 \times 2 \times 2 \: )

➺\: 4 + 3 \: ( \: 10 - 8 \: )

➺\: 4 + 3 \: ( \: 2 \: )

➺\: 4 + 6

➺\: 10

<h3><u>Note</u>:-</h3>

\sf\pink{PEMDAS\: rule.}

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

6 0
3 years ago
Read 2 more answers
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