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Bas_tet [7]
3 years ago
10

David made a line plot of how many miles he biked each day for two weeks. How many miles did he bike in all?​

Mathematics
1 answer:
devlian [24]3 years ago
5 0

We need to know how many miles he biked one day first. Then you times how many miles he biked by 14 (2 weeks).

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Find the variable 15 = 5 − 13
Lyrx [107]

Answer:

0.4

Step-by-step explanation:

15 = 5p - 13

-13 = 5p -13

----------------  ( subtract 13 on both sides )

 <u> 2 = 5p</u>

  5 = 5p

----------------  ( divide 2 by 5 )

  p = 0.4

( p equals 0.4 )

7 0
3 years ago
Write the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to 2x + y = -5. Include your work
STALIN [3.7K]
Paralell to 2x+y=-5
means it has same slope
means it is in form
2x+y=c where we have to find c
convert to slope intercept
minus 2x both sides

xint of 2
xint is where th eline crosses the x axis or where y=0, x=2

2(2)+0=c
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4=c


the equation is 2x+y=4
4 0
3 years ago
Please help me with steps ​
Kitty [74]

Answer:

12 if x_y

Step-by-step explanation:

12= 3x4 (I'm sorry for this, I need points)

8 0
3 years ago
Qual é o mdc de 340 e 728?
Diano4ka-milaya [45]
MDC and largest number that can divide two numbers while 
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<span>170.364 2 </span>
<span>85 182  </span>
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7 0
3 years ago
Derivatives of inverse trigonometric functions please explain answers
Jobisdone [24]

I'll explain how to do the first one:-

y = cos-1(x2)

This can be described as ' a function of a function'   x^2 is a function of x and cos-1(x^2) is a function of x^2.

We need to  apply the chain rule.

Personally I find this  easier to understand if i let u = x^2, so

If y = f(u) and u is a function of x then

dy/dx = dy/ du * du/dx

Here u = x^2  and y = cos-1(u)

du/dx = 2x

so dy/dx = d(cos-1(x^2) dx = dy/du * du/dx


= -1 / √(1 - u^2) * 2x

= -2x / √(1 - u^2)    

= -2x / √(1 - (x^2)^2)

= -2x / √(1 - x^4)

I hope this helps. but if not. you might like to employ the formulae in the question - The square boxes contain the 'u' s in my answer. These formulae are equivalent to my explanation.

6 0
3 years ago
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