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3 years ago

Help Please!!

Mathematics

2 answers:

aniked [119]3 years ago

5 0

Answer:

Step-by-step explanation:

vaieri [72.5K]3 years ago

4 0

The ansewer is dddddddddddddddddddd

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Theresa has $12 in nickels and quarters. If she has the same number of each kind of coin, how many nickels and quarters does she

postnew [5]

Answer: She has 40 nickels and 40 quarters .

Step-by-step explanation:

Let be "n" the number of nickels Theresa has and "q" the number of quarters Theresa has.

You know that she has a total of $12 in nickels and quarters. In cents, this is:

$\$12*100=1,200\ cents$

Then, based on this you can write the following expression:

$5n+25q=1,200$

Since $n=q$ , you can rewrite it as:

$5n+25n=1,200$

Solving for "n", you get:

$30n=1,200\\\\n=\frac{1,200}{30}\\\\n=40$

Therefore she has 40 nickels and 40 quarters .

7 0

3 years ago

The cooking club made some pies to sell at a basketball game to raise money for the school dance. The parents association contri

-BARSIC- [3]

The answer is 12 pies. If you sell 60 pieces and there are 5 pieces in each pie then you would Have 12 pies. X = pies 5x =60 To undo this you would have to divide 60 by 5.

6 0

3 years ago

Mae Ling earns a weekly salary of $310 plus a 6.5% commission on sales at a gift shop. How much would

Kryger [21]

Answer:

$325

Step-by-step explanation:

Mae Ling earns a weekly salary of $325 plus a 6.5% commission on sales at a gift shop. How much would she make in a work week if she sold $4,800 worth of merchandise?

7 0

2 years ago

Read 2 more answers

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$