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3 years ago

7

Guided Practice

1 answer:

PolarNik [594]3 years ago

5 0

Answer:

uhhhhhhhhhhhhhh

Step-by-step explanation:

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Need help ASAP (IMAGE ATTACHED)

Phantasy [73]

Answer:

The answer is B

Step-by-step explanation:

It becomes 8y = -3x + 12.

Then divide by 8 on both sides.

y = -0.375+1.5

This you can turn it into a fraction which is y = -3/8 + 1.5

3 0

2 years ago

Read 2 more answers

Factor: 4y2−18y−14

AnnyKZ [126]

The answer is B.2(2y2-9y+7)

6 0

3 years ago

How many pairs of numbers add up to 11?l have used calculation find their is 6 pairs But like to know • How could I change how I

Rasek [7]

<span> If all numbers are greater than zero and no repeated numbers exist these are the 5 possible combinations:

1 + 2 + 8
1 + 3 + 7
1 + 4 + 6
2 + 3 + 6
2 + 4 + 5.

If one number is allowed to be zero and no repeated numbers exist these are 5 combinations:
</span><span> 0 + 11
1 + 1 + 9
2 + 2 + 7
3 + 3 + 5
4 + 4 + 3
5 + 5 + 1
</span><span>
Hope this helps

</span>

6 0

3 years ago

Read 2 more answers

Clark and Lana take a 30-year home mortgage of $128,000 at 7.8%, compounded monthly. They make their regular monthly payments fo

svp [43]

Answer:

Step-by-step explanation:

From the given information:

The present value of the house = 128000

interest rate compounded monthly r = 7.8% = 0.078

number of months in a year n= 12

duration of time t = 30 years

To find their regular monthly payment, we have:

$PV = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{r}{n})^{-nt}}{\dfrac{r}{n}} \end {bmatrix}$

$128000 = P \begin {bmatrix} \dfrac{1 - (1 + \dfrac{0.078}{12})^{- 12*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

128000 = 138.914 P

P = 128000/138.914

P = $921.433

∴ Their regular monthly payment P = $921.433

To find the unpaid balance when they begin paying the $1400.

when they begin the payment ,

t = 30 year - 5years

t= 25 years

$PV= 921.433 \begin {bmatrix} \dfrac{1 - (1 - \dfrac{0.078}{12})^{25*30}}{\dfrac{0.078}{12}} \end {bmatrix}$

PV = $121718.2714

C) In order to estimate how many payments of $1400 it will take to pay off the loan, we have:

$121718.2714 = \begin {bmatrix} \dfrac{1300 (1 - \dfrac{12.078}{12}))^{-nt}}{\dfrac{0.078}{12}} \end {bmatrix}$

$121718.2714 = 200000 \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$\dfrac{121718.2714}{200000 } = \begin {bmatrix} (1 - \dfrac{12.078}{12}))^{-nt} \end {bmatrix}$

$0.60859 = \begin {bmatrix} (1 - \dfrac{12}{12.078}))^{nt} \end {bmatrix}$

$0.60859 = (0.006458)^{nt}$

$nt = \dfrac{0.60859}{0.006458}$

nt = 94.238 payments is required to pay off the loan.

How much interest will they save by paying the loan using the number of payments from part (c)?

The total amount of interest payed on $921.433 = 921.433 × 30(12) years

= 331715.88

The total amount paid using 921.433 and 1300 = (921.433 × 60 )+( 1300 + 94.238)

= 177795.38

The amount of interest saved = 331715.88 - 177795.38

The amount of interest saved = $153920.5

6 0

4 years ago

the directions are : find the constant of proportionality for the graph and write in the form y = kx.n

Lelechka [254]

here is the answer (A) y=1/5 x

5 0

3 years ago