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tia_tia [17]
2 years ago
14

Need help ASAP (IMAGE ATTACHED)​

Mathematics
2 answers:
const2013 [10]2 years ago
8 0
B or c . I think it’s b though I don’t know for sure
Phantasy [73]2 years ago
3 0

Answer:

The answer is B

Step-by-step explanation:

It becomes 8y = -3x + 12.

Then divide by 8 on both sides.

y = -0.375+1.5

This you can turn it into a fraction which is y = -3/8 + 1.5

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Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
One day in the playground,the ratio of the number of boy to the number of girl is 3:5 later 6girls come, 9boy leave, the ratio o
choli [55]

Answer:

The number of boys are 18 and the number of girls are 30.

Step-by-step explanation:

The ratio of number of girls to the boys = 3 : 5

Let the number of girls is g and boys is b initially.

b : g = 3 : 5

5 b = 3 g ..... (1)

Now, girls are 6 + g and boys are b - 9

So, the ratio is

(b - 9) : (6 + g) = 1 : 4

4 b - 36 = 6 + g

4 b - g = 42 .... (2)

From ( 1 ) and ( 2 )

4 b - \frac {5 b}{3}= 42\\\\\frac{7 b }{3} = 42\\\\b = 18

And , g = 5 x 18/3 = 30

So, the number of boys are 18 and the number of girls are 30.  

7 0
3 years ago
Which recursive formula can be used to generate the sequence shown where f(1)=9.6 and n is greater than or equal to 1?
S_A_V [24]
The formula is f(x) = 10x + 5
3 0
3 years ago
A school play earned over $250 from selling tickets, which cost $11 each. Which of the following inequalities models this situat
jeyben [28]
Its B because its supposed to be OVER 250
7 0
3 years ago
Read 2 more answers
5. Isabella is calculating the interest earned on a deposit of $3,000 in an account that earns 4% simple interest after 6 years.
Anna35 [415]

Answer:

B. 300 dollars is 5he answers

6 0
3 years ago
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