Part A:Bees: f ( t ) = 1,500 * 0.88^tFlowering plants: g ( t ) = 800 - 25 tPart B :f ( 6 ) = 1,500 * 0.88^6 = 696.6 ≈ 697
g ( 6 ) = 800 - 25 * 6 = 800 - 150 = 650Part C :f ( 7 ) = 1,500 * 0.88^7 = 613g ( 7 ) = 800 - 7 * 25 = 625f ( 7 ) ≈ g ( 7 )After approximately 7 months.
Answer:
about 3 seconds
Step-by-step explanation:
hope this helps
ince the problem is only asking for 4 years, we can just calculated it out year by year. Recall the formula for compounding interest: A = P(1+r)n, where A is the total amount, P is the principle (amount you start with), r is the interest rate per period of time, and n is the number of periods (in this case, r is annual interest rate, so n is number of years). At the beginning (Year 0), Lou starts off with 10000: A = 10000 At the end of Year 1, Lou earned interest on that amount, plus he has deposited another 5000: A = 10000(1.08) + 5000 End of Year 2, Lou's interest from the year 0 amount has compounded, he has started earning interest on the amount deposited last year, and he deposits another 5000: A = 10000(1.08)2 + 5000(1.08) + 5000 End of Year 3, same idea. Lou has earned compounding interest on all existing deposits, and deposits another 5000: A = 10000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 End of Year 4, same idea: A = 10000(1.08)4 + 5000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 = 36135.45
Answer:
[see below]
Step-by-step explanation:
A function's inputs do not repeat. This means that any point with the x-value not repeated with the other points can be added to ensure that it continues as a function.
In this scenario:
{x| x ≠ -7, 4, 0, -2}
A point that does not have the x-value of -7, 0, 4, and -2 could be added to the relation to ensure it continues to be a function.
Hope this helps.
