Question

Given you or a person holding a kite string 100 feet long write and draw what the height or altitude the kite is off the ground if the angle of elevation is 49 HELP!

Answer 1

Answer: $75.47\ ft$

Step-by-step explanation:

Given

String of the kite is $l=100\ ft$

Angle of elevation $\theta=49^{\circ}$

suppose altitude of the kite is h

from the figure, we can write

$\Rightarrow \sin 49^{\circ}=\dfrac{h}{100}\\\\\Rightarrow h=100\sin 49^{\circ}\\\\\Rightarrow h=75.47\ ft$

Thus, the altitude of the kite is $75.47\ ft$