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IRISSAK [1]
3 years ago
9

Given you or a person holding a kite string 100 feet long write and draw what the height or altitude the kite is off the ground

if the angle of elevation is 49 HELP!
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
8 0

Answer: 75.47\ ft

Step-by-step explanation:

Given

String of the kite is l=100\ ft

Angle of elevation \theta=49^{\circ}

suppose altitude of the kite is h

from the figure, we can write

\Rightarrow \sin 49^{\circ}=\dfrac{h}{100}\\\\\Rightarrow h=100\sin 49^{\circ}\\\\\Rightarrow h=75.47\ ft

Thus, the altitude of the kite is 75.47\ ft

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In the past ten years, the population of a city decreased from 90,000 to 75,000 Find the percent decrease.
vfiekz [6]
The answer is 31.5%.
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3 years ago
A pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. The height, h, of th
Gennadij [26K]
<h2>Explanation:</h2>

In this problem we have a pumpkin is launched from the top of a 20 foot tall platform at an initial velocity of 84 feet per second. So the height, h, of the pumpkin at time t seconds after the launch can be modeled by the equation:

h(t) = -16t^2 + 84t + 20

So this is the equation of a parabola. The maximum of this parabola occurs at its vertex. So let's find this vertex:

\text{The x-value of the vertex is}: \\ \\ t=-\frac{b}{2a} \\ \\ \\ Where: \\ \\ a=-16 \\ \\ b=84 \\ \\ c=20 \\ \\ \\ t=-\frac{84}{2(-16)} \\ \\ t=-\frac{84}{-32} \\ \\ t=\frac{21}{8}=2.625 \\ \\ h(2.625)=-16(2.625)^2+84(2.625)+20 \\ \\ h(2.625)=-110.25+220.5+20 \\ \\ h(2.625)=130.25m

Finally, the maximum occurs at time 2.625 seconds when the height is 130.25m

8 0
3 years ago
the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

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Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

5 0
3 years ago
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Answer:
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2 years ago
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a_sh-v [17]

Answer:

Step-by-step explanation:

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2 years ago
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