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Alika [10]
3 years ago
12

Helppppppppppppppppppppppppppppppp

Mathematics
1 answer:
Agata [3.3K]3 years ago
5 0

Assuming you need to find a multiple of both 3 and 11 to be your answer, the answer should be 33 days.

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3 years ago
Luis has 3 1/3 yards of ribbon to use for two separate presents, one of which is very large. If Luis uses 2 1/2 yards to decorat
never [62]

Answer:

\frac{5}{6} yards

Step-by-step explanation:

Luis had 3\frac{1}{3} yards of ribbon in total to use for two presents. For the first present Luis used 2\frac{1}{2} yards of the ribbon.

Since she had 3\frac{1}{3} yards in total and she used  2\frac{1}{2} yards from it, the amount of ribbon left for second present can be obtained by taking out(subtracting)  2\frac{1}{2} yards from 3\frac{1}{3}.

So, the number of yards of ribbon left for second present will be:

3\frac{1}{3}-2\frac{1}{2}\\\\ =\frac{10}{3}-\frac{5}{2}\\\\ =\frac{10(2)-5(3)}{2 \times 3}\\\\ =\frac{20-15}{6}\\\\ =\frac{5}{6}

This means Luis had \frac{5}{6} yards of ribbon for the second present.

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