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Alika [10]
3 years ago
12

Helppppppppppppppppppppppppppppppp

Mathematics
1 answer:
Agata [3.3K]3 years ago
5 0

Assuming you need to find a multiple of both 3 and 11 to be your answer, the answer should be 33 days.

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If Vector u=(5,-7) and v=(-11,3), 2v-6u=_____ and ||2v-6u||≈_____
Sauron [17]
<h2>Answer:</h2>

2\vec{v}-6\vec{u}=(-52,48) \\ \\ ||2\vec{v}-6\vec{u}||=75.28}

<h2>Step-by-step explanation:</h2>

In this problem we have two vectors:

\vec{u}=(5,-7) \ and \ \vec{v}=(-11,3)

So we need to find two things:

2\vec{v}-6\vec{u}

and:

||2\vec{v}-6\vec{u}||

FIRST:

In this case we have the multiplication of vectors by scalars. A scalar is a simple number, so:

2\vec{v}-6\vec{u} \\ \\ Replace \ \vec{v} \ and \ \vec{u} \ by \ the \ given \ vectors: \\ \\ 2(-11,3)-6(5,-7) \\ \\ Multiply \ each \ component \ by \ the \ corresponding \ scalar:\\ \\ (2\times (-11),2\times 3)+(-6\times 5,-6\times (-7)) \\ \\ (-22,6)+(-30,42) \\ \\ Sum \ of \ vectors: \\ \\ (-22-30,6+42) \\ \\ \therefore \boxed{(-52,48)}

SECOND:

If we name:

\vec{w}=2\vec{v}-6\vec{u}

Then, ||2\vec{v}-6\vec{u}|| is the magnitude of the vector \vec{w}. Therefore:

||\vec{w}||=||2\vec{v}-6\vec{u}|| \\ \\ ||\vec{w}||=||(-52,48)|| \\ \\ ||\vec{w}||=\sqrt{(-58)^2+48^2} \\ \\ ||\vec{w}||=\sqrt{3364+2304} \\ \\ ||\vec{w}||=\sqrt{5668} \\ \\ \boxed{||\vec{w}||=75.28}

5 0
3 years ago
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What is the relative frequency of male passengers?
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A. 0.15 Because its making me type twenty characters.
3 0
3 years ago
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If right answer good review
Nookie1986 [14]

Answer:

Bottom right graph is the correct answer

3 0
2 years ago
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How do you factor 2x^4 - 2y^4
labwork [276]
First factor out 2 

2(x^4 - y^4) 

Rewrite it as ((x^2)^2) and ((y^2)^2) 

Then you get..

2 ((x^2)^2) - (y^2)^2)) 

Now both terms are perfect squares, factor using the difference of squares formula, a^2 + b^2 = (a+b)(a-b) 

a= x^2 and b= y^2 

2((x^2 + y^2)(x+y)(x-y))

clean it up!

2(x^2 + y^2)(x+y)(x-y) 


7 0
3 years ago
Factorize 3x4y3 – 48y3.
r-ruslan [8.4K]

Answer:it’s 3y3 (x2 +4) (x +2 (x-2) hope this helps.

Step-by-step explanation:

6 0
3 years ago
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